用户如何使用 sequelize postgres nodejs 相互喜欢和不同 post？

Question

我正在努力实现用户可以互相喜欢post。

这是我的点赞模型：

const Likes = db.define("Likes", {

id: {
allowNull: false,
autoIncrement: true,
primaryKey: true,
type: Sequelize.INTEGER,
  },
  PostId: {
  type: Sequelize.INTEGER,
   references: {
  model: "Post",
  key: "id",
   },
onUpdate: "cascade",
onDelete: "cascade",
 },
 userId: {
type: Sequelize.INTEGER,
references: {
  model: "User",
  key: "id",
},
onUpdate: "cascade",
onDelete: "cascade",
 },
 createdAt: {
allowNull: false,
type: Sequelize.DATE,
 },
updatedAt: {
allowNull: false,
type: Sequelize.DATE,
  },

这是我的 Post 型号：

id: {
  type: Sequelize.INTEGER,
  primaryKey: true,
  autoIncrement: true,
},
title: {
  type: Sequelize.STRING,
},
userId: {
  type: Sequelize.INTEGER,
},

这是我的用户模型：

id: {
  type: Sequelize.INTEGER,
  primaryKey: true,
  autoIncrement: true,
},
name: {
  type: Sequelize.STRING,
},

这是我的联想：

db.Likes.belongsTo(db.User, { foreignKey: "userId", targetKey: "id" });
db.Likes.belongsTo(db.Post, { foreignKey: "PostId", targetKey: "id" });
db.Post.hasMany(db.Likes, { foreignKey: "PostId", targetKey: "id" });
db.User.hasMany(db.Likes, { foreignKey: "userId", targetKey: "id" });

这是我的 post 和删除请求：

router.post("/:id/likes", async (req, res, next) => {
const { userId } = req;

const PostId = req.params.id;
const post = await Post.findByPk(PostId);

  if (!post)
return res
  .status(404)
  .send({ message: "Post cannot be found or has been removed" });

let like = await Likes.findOne({
  where: { [Op.and]: [{ PostId: req.params.id }, { userId: 
 req.userId  }] },
 });

  if (!like) {
  let newLike = await Likes.create({
  userId: userId,
  PostId: req.params.id,
   });
   return res.json(newLike);
   } else {
  await like.destroy();
  return res.send();
   }
  });

我不断收到 UnhandledPromiseRejectionWarning：错误：WHERE 参数“userId”具有无效的“未定义”值。

在我的前端，当我执行 console.log(user.id) 时，我得到了喜欢 post 的用户的 ID，当我执行 console.log(post.id) 我得到了被点赞的 post 的 ID。

更新

在前端，这是我将数据发送到后端的方式：

const likePost = (like) => {
 const data = new FormData();
 data.append("userId",like.userId);
 data.append("PostId",like.PostId)

console.log(like.PostId) // the post id is shown in terminal
console.log(like.userId) // the user id is shown in terminal

console.log(like)

return client.post(`/posts/${like.PostId}/likes`, data);
}

console.log（喜欢）returns这个

Object {
 "PostId": 489,
 "userId": 43,
 }

这是 post 和喜欢 post 的用户的正确 ID。

后端是我的 post 请求：

router.post("/:id/likes", async (req, res, next) => {

 console.log(req.body); // returns an empty object {}

 const PostId = req.params.id;
 const post = await Post.findByPk(PostId);

  if (!post)
  return res
  .status(404)
  .send({ message: "Post cannot be found or has been removed" });

 let like = await Likes.findOne({
  where: {
  [Op.and]: [
    { PostId: req.params.id },
    //  { userId: req.body.userId }
  ],
  },
  });

  if (!like) {
let newLike = await Likes.create({
  // userId: req.body.userId,
  PostId: req.params.id,
});
return res.json(newLike);
  } else {
await like.destroy();
return res.send();
 }
});

这样做之后，我仍然无法在 req.body

中获取用户 ID

Answer 1

您的 findOne 查询似乎需要 req.params.userId，假设 userId 已在请求的参数中传递：

{ userId: req.params.userId }

Answer 2

client.post(/posts/${like.PostId}/likes, { userId: like.userId, PostId:like.PostId })

在前端使用它，我能够在后端访问 req.body，谢谢@Anatoly

用户如何使用 sequelize postgres nodejs 相互喜欢和不同 post？

How can users like and unlike each others post using sequelize postgres nodejs?

postgresql

node.js

sequelize.js