Selenium 选择一个元素并使用 python 单击按钮
Selenium selecting an element and clicking the button using python
通过检查复制元素:
</span></div></div></div><button class="primary LanguageSelectionForm_submitButton SimpleButton_root ButtonOverrides_root" label="Continue">Continue</button></div>
我正在尝试按继续按钮转到。下一页
我试过:
driver.find_element_by_xpath("//button[(@class='primary LanguageSelectionForm_submitButton SimpleButton_root ButtonOverrides_root')
错误:
selenium.common.exceptions.NoSuchElementException: Message: no such element: Unable to locate element: {"method":"xpath","selector":"//button[(@class='primary LanguageSelectionForm_submitButton SimpleButton_root ButtonOverrides_root')]"}
还有:
button = driver.find_element_by_class_name("primary LanguageSelectionForm_submitButton SimpleButton_root ButtonOverrides_root")
再次产生NoSuchElementException
有人知道吗?
不要全名这样做:
button = driver.find_element_by_class_name("LanguageSelectionForm_submitButton")
通过使用 label="continue"
验证 LanguageSelectionForm_submitButton
在文档中是否唯一但不是唯一的完整条件
谢谢
要将带有文本的元素标识为 Continue,您可以使用以下任一方法 :
使用css_selector
:
button = driver.find_element_by_css_selector("button.primary.LanguageSelectionForm_submitButton.SimpleButton_root.ButtonOverrides_root[label='Continue']")
使用xpath
:
button = driver.find_element_by_xpath("//button[@class='primary LanguageSelectionForm_submitButton SimpleButton_root ButtonOverrides_root' and text()='Continue']")
理想情况下,要识别您需要为 element_to_be_clickable()
引入 WebDriverWait 的元素,您可以使用以下任一方法 :
使用CSS_SELECTOR
:
button = WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.CSS_SELECTOR, "button.primary.LanguageSelectionForm_submitButton.SimpleButton_root.ButtonOverrides_root[label='Continue']")))
使用XPATH
:
button = WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//button[@class='primary LanguageSelectionForm_submitButton SimpleButton_root ButtonOverrides_root' and text()='Continue']")))
注意:您必须添加以下导入:
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC
通过检查复制元素:
</span></div></div></div><button class="primary LanguageSelectionForm_submitButton SimpleButton_root ButtonOverrides_root" label="Continue">Continue</button></div>
我正在尝试按继续按钮转到。下一页
我试过:
driver.find_element_by_xpath("//button[(@class='primary LanguageSelectionForm_submitButton SimpleButton_root ButtonOverrides_root')
错误:
selenium.common.exceptions.NoSuchElementException: Message: no such element: Unable to locate element: {"method":"xpath","selector":"//button[(@class='primary LanguageSelectionForm_submitButton SimpleButton_root ButtonOverrides_root')]"}
还有:
button = driver.find_element_by_class_name("primary LanguageSelectionForm_submitButton SimpleButton_root ButtonOverrides_root")
再次产生NoSuchElementException
有人知道吗?
不要全名这样做:
button = driver.find_element_by_class_name("LanguageSelectionForm_submitButton")
通过使用 label="continue"
验证LanguageSelectionForm_submitButton
在文档中是否唯一但不是唯一的完整条件
谢谢
要将带有文本的元素标识为 Continue,您可以使用以下任一方法
使用
css_selector
:button = driver.find_element_by_css_selector("button.primary.LanguageSelectionForm_submitButton.SimpleButton_root.ButtonOverrides_root[label='Continue']")
使用
xpath
:button = driver.find_element_by_xpath("//button[@class='primary LanguageSelectionForm_submitButton SimpleButton_root ButtonOverrides_root' and text()='Continue']")
理想情况下,要识别您需要为 element_to_be_clickable()
引入 WebDriverWait 的元素,您可以使用以下任一方法
使用
CSS_SELECTOR
:button = WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.CSS_SELECTOR, "button.primary.LanguageSelectionForm_submitButton.SimpleButton_root.ButtonOverrides_root[label='Continue']")))
使用
XPATH
:button = WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//button[@class='primary LanguageSelectionForm_submitButton SimpleButton_root ButtonOverrides_root' and text()='Continue']")))
注意:您必须添加以下导入:
from selenium.webdriver.support.ui import WebDriverWait from selenium.webdriver.common.by import By from selenium.webdriver.support import expected_conditions as EC