截断计算列的结果

Question

我正在尝试从计算列的结果中截断或舍入百分比。

select DISTINCT woo.si_number, woo.bill_name,  max (wts.est_hours) *70.00 +  sum (DISTINCT                  wob.unit_price ) as total,  
truncate (max (wts.est_hours) *70.00  +  sum (DISTINCT wob.unit_price ) - sum (DISTINCT    stk.unit_cost))  / (max (wts.est_hours) *70.00 +  sum (DISTINCT wob.unit_price )) as percentage 
                                           
                                           
from wo_operation woo join wo_bom wob on wob.woo_auto_key = woo.woo_auto_key
                  join stock stk on stk.pnm_auto_key = wob.pnm_auto_key
                  join wo_task wot on wot.woo_auto_key = woo.woo_auto_key
                  join wo_task_skills wts on wts.wot_auto_key = wot.wot_auto_key
                 
                  
             
where stk.historical_flag = 'F' and                     
  woo.si_number = 'WB6222'
group by woo.si_number, woo.bill_name
order by woo.si_number

结果有很多小数位，只需要2位。

B6222   Company Name      1711.63        0.4693829858088488750489299673410725448841

杰夫

Answer 1

这是你的表情：

truncate (
    max (wts.est_hours) * 70.00  
    + sum(DISTINCT wob.unit_price) 
    - sum(DISTINCT stk.unit_cost)
)  / (
    max (wts.est_hours) * 70.00 
    +  sum(DISTINCT wob.unit_price)
) as percentage

您（似乎）希望围绕整个计算进行截断，而不是仅针对分子进行截断。所以：

trunc (
    (
        max (wts.est_hours) *70.00  
        + sum(DISTINCT wob.unit_price) 
        - sum(DISTINCT stk.unit_cost)
    )  / (
        max (wts.est_hours) *70.00 
        +  sum(DISTINCT wob.unit_price)
    ),
    2
) as percentage

备注：

truncate() 与 Oracle 无关。
trunc() 不是舍入函数：它只是删除额外的数字。如果要四舍五入...请改用 round()。
sum(distinct ...) 是一个非常原始的东西；仅从您的问题中无法判断这是否真的是您想要的...我可能只是建议您不要使用它，除非您真的知道为什么要这样做。

group by

select distinct 是不必要的

截断计算列的结果

Truncate results from a calculated column

sql

oracle

aggregate-functions