如何获得 Java 代码覆盖率的完整覆盖率？ Junit 5 日食 IDE

Question

我正在为一门课程做作业，我需要全面了解此方法

public void ourcompanyname(String companyName) {
        if (companyName == ("")) {
            throw new AirlineException("Warning. The company must have a name !");}

---->这是构造函数

public String getCompanyName() {
        return companyName;
    }
    /**
     * @param companyName the companyName to set
     */
    public void setCompanyName(String companyName) {
        this.companyName = companyName;

----->这是我使用的测试

public void testSet() throws AirlineException { 
        airlinecompany.setCompanyName((""));

Assertions.assertEquals((""),airlinecompany.getCompanyName());
Assertions.assertThrows(AirlineException.class,()->airlinecompany.ourcompanyname(("")));

----->问题是我在测试这段代码时得到了 50% 的覆盖率。 ("") 字符串表示一个空白字段，因此当您不填写名称时，您会得到一个 AirlineException。但我也想测试它是否有像“FLYAIR”这样的字符串，它不应该抛出异常。我有什么选择？更好地编码空白字段 ("") 或仅更改此字段？

提前好多了！

Answer 1

尝试这样的事情：---

    @Test
    public void testUsernameIsNull() {
     
        Throwable exception = Assertions.assertThrows(
                AirlineException.class, () -> {
                    Airlinecompany airlinecompany = new Airlinecompany();
                    airlinecompany.setName("");
                }
        );
     
        Assertions.assertEquals("Warning. The company must have a name !", exception.getMessage());

if(true){

Airlinecompany airlinecompany = new Airlinecompany();
                    airlinecompany.setName("FLYAIR");
        Assertions.assertEquals(("FLYAIR"),airlinecompany.getCompanyName());
}
    }

希望它能解决您的问题。

如何获得 Java 代码覆盖率的完整覆盖率？ Junit 5 日食 IDE

How to get full coverage for Java Code Coverage? Junit 5 Eclipse IDE

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