Django 模型中的下拉列表

Dropdown in Django Model

我想在 Django models.py 中创建一个字段,它将呈现为下拉列表,用户可以从那里 select 选择选项。

如果我有5个选择:

我应该如何在 models.pyForms.py 中编写代码,以便模板将其呈现为下拉元素?

在模型中使用 choices 选项指定 CharField 或 IntegerField https://docs.djangoproject.com/en/dev/ref/models/fields/#choices and use ModelForm https://docs.djangoproject.com/en/dev/topics/forms/modelforms/

从模型到模板:

models.py

COLOR_CHOICES = (
    ('green','GREEN'),
    ('blue', 'BLUE'),
    ('red','RED'),
    ('orange','ORANGE'),
    ('black','BLACK'),
)

class MyModel(models.Model):
  color = models.CharField(max_length=6, choices=COLOR_CHOICES, default='green')

forms.py

class MyModelForm(ModelForm):
    class Meta:
        model = MyModel
        fields = ['color']

views.py

class CreateMyModelView(CreateView):
    model = MyModel
    form_class = MyModelForm
    template_name = 'myapp/template.html'
    success_url = 'myapp/success.html'

template.html

<form action="" method="post">{% csrf_token %}
    {{ form.as_p }}
    <input type="submit" value="Create" />
</form>

或仅显示您的 select 字段:

{{ form.color }}

Django 版本 3.0 和更高版本中更好的选择:

您可以使用继承自新 models.TextChoices class 的内部 classes。这也提供了一种方便的方式来提供人类可读(和可翻译)的标签,并为程序员提供了一个很好的界面。

Official Django documentation

from django.utils.translation import gettext_lazy as _

class Student(models.Model):

    class YearInSchool(models.TextChoices):
        FRESHMAN = 'FR', _('Freshman')
        SOPHOMORE = 'SO', _('Sophomore')
        JUNIOR = 'JR', _('Junior')
        SENIOR = 'SR', _('Senior')
        GRADUATE = 'GR', _('Graduate')

    year_in_school = models.CharField(
        max_length=2,
        choices=YearInSchool.choices,
        default=YearInSchool.FRESHMAN,
    )

    def is_upperclass(self):
        return self.year_in_school in {
            self.YearInSchool.JUNIOR,
            self.YearInSchool.SENIOR,
        }

###########
# human readable text can then be called by...
Student.YearInSchool.Junior.label

# or from an instance by <instance>.get_<innerclass name>_display() like...
student_inst.get_yearinschool_display()