UnicodeEncodeError: 'ascii' codec can't encode character at special name

Question

我的 python（2.7 版）脚本运行很好地从本地 html 文件中获取一些公司名称，但是当涉及到某些特定的国家/地区名称时，它会出现此错误"UnicodeEncodeError: 'ascii' codec can't encode character"

特别是这个公司名出现时报错

公司名称：Kühlfix Kälteanlagen Ing.Gerhard Doczekal & Co. KG

无法处理link

Traceback (most recent call last): 
  File "C:\Python27\Process2.py", line 261, in <module>
    flog.write("\nCompany Name: "+str(pCompanyName))
UnicodeEncodeError: 'ascii' codec can't encode character u'\xfc' in position 9: ordinal not in range(128)

错误在这行代码中给出：

if companyAlreadyKnown == 0:
   for hit in soup2.findAll("h1"):
       print "Company Name: "+hit.text
       pCompanyName = hit.text
       flog.write("\nCompany Name: "+str(pCompanyName))
       companyObj.setCompanyName(pCompanyName)

Answer 1

尝试在脚本开头将系统默认编码设置为 utf-8，以便所有字符串都使用该编码。

例子-

import sys
reload(sys)
sys.setdefaultencoding('utf-8')

上面应该设置默认编码为 utf-8 .

Answer 2

你真的很想这样做

flog.write("\nCompany Name: "+ pCompanyName.encode('utf-8'))

这是本 unicode presentation（幻灯片 32 到 35）中描述的 "encode late" 策略。

UnicodeEncodeError: 'ascii' codec can't encode character at special name

UnicodeEncodeError: 'ascii' codec can't encode character at special name

python

unicode

encoding

ascii

beautifulsoup