如何使用 pandas 获取两个日期之间的天数

How to get number of days between two dates using pandas

我正在尝试使用以下函数获取两个日期之间的天数

df['date'] = pd.to_datetime(df.date)

# Creating a function that returns the number of days
def calculate_days(date):
    today = pd.Timestamp('today')
    return today - date

# Apply the function to the column date
df['days'] = df['date'].apply(lambda x: calculate_days(x))

结果是这样的

153 days 10:16:46.294037

但我想让它说 153。我该如何处理?

为了提高性能,您可以在不使用 apply 的情况下减去值以避免循环 使用 Series.rsub 从右侧减去:

df['date'] = pd.to_datetime(df.date)
df['days'] = df['date'].rsub(pd.Timestamp('today')).dt.days

工作方式:

df['days'] = (pd.Timestamp('today') - df['date']).dt.days

如果想使用您的解决方案:

df['date'] = pd.to_datetime(df.date)

def calculate_days(date):
    today = pd.Timestamp('today')
    return (today - date).days

df['days'] = df['date'].apply(lambda x: calculate_days(x))

或者:

df['date'] = pd.to_datetime(df.date)

def calculate_days(date):
    today = pd.Timestamp('today')
    return (today - date)

df['days'] = df['date'].apply(lambda x: calculate_days(x)).dt.days
df['date'] = pd.to_datetime(df.date)

a) pandas

(pd.Timestamp("today") - df.date).days

b) 这个 numpy 构建函数允许你 select 一个周掩码

 np.busday_count(df.date.date(), pd.Timestamp("today").date(), weekmask=[1,1,1,1,1,1,1])