如何将不同项目的小时和分钟相加checkin/checkout

Question

我们有一个 table 叫：

活动

每一行都有这个值：

id
类型 (checkin/checkout)
开始（varchar 2020-11-30 15:45）

给定一个特定的日子，例如 11-30-2020，假设我们有几个 checkin/checkout 如何对这些天的小时和分钟求和？

这就是我们试图获取全天总和的函数：

 function sum_all_hours_by_day($fxemploye_id, $day){
    $core_settings = Setting::first();

    $hours = 0;
    $date = date_create($day);
    $date_format = date_format($date, 'Y-m-d');

    $date_format_start = $date_format .  " 00:00";
    $date_format_end = $date_format . " 23:59";

    $options = array('conditions' => array('fxemploye_id = ? and start >= ? and start <= ?', $fxemploye_id, $date_format_start,$date_format_end));
    $activities = FxemployeHasActivity::all($options);

    $i = 0;
    $d1 = 0; //Checkin
    $d2 = 1; //Checkout
    foreach(array($activities) as $ibd){

        $date1 = $ibd[$d1]->start;
        $date2 = $ibd[$d2]->end;

        $timestamp1 = strtotime($date1);
        $timestamp2 = strtotime($date2);


        if($timestamp1 == true && $timestamp2 == true){
            $sum = abs((int)$timestamp2 - (int)$timestamp1)/(60*60); 
            $hours = $hours + $sum;
        }
        $d1 = $d1++;
        $d2 = $d2++;
        $i++;
    }


    return $hours;
}

Answer 1

我认为您所追求的可以在 MySQL 本身中很容易地实现（假设您使用的是 MySQL）：

SELECT SUM(UNIX_TIMESTAMP(start) - UNIXTIMESTAMP(end))
FROM activities
WHERE `start` > X and `end` < y AND fxemploye_id = N

然后在 Codeigniter 中使用 QueryBuilder 这看起来像这样：

$db = $this->db;
$db->select('SUM(UNIX_TIMESTAMP(start) - UNIXTIMESTAMP(end)) as Result');
$db->where('start >',$date_format_start);
$db->where('end <',$date_format_end);
$db->where('fxemploye_id',$fxemploye_id);
$data = $db->get('activities')->result_array();

Answer 2

我已经用一种方法解决了，但我认为这不是最好的方法，但假设数据库结构按原样给出，它可以作为一个函数工作。如果有人能做到这一点，那将是受欢迎的。

  function sum_all_hours_by_day($fxemploye_id, $day){
    $core_settings = Setting::first();


    //You can debug forcing the $day = '2020-11-19';
    $date = date_create($day);
    $date_format = date_format($date, 'Y-m-d');

    //Adding the time as we don't have that from database
    $date_format_start = $date_format .  " 00:00";
    $date_format_end = $date_format . " 23:59";

    $options = array('conditions' => array('fxemploye_id = ? and start >= ? and start <= ?', $fxemploye_id, $date_format_start,$date_format_end));

    //Getting all checkins between two days as a range
    $activities = FxemployeHasActivity::all($options);

    //We get the $d1 as a first checkin 2020-11-19 08:15
    //We get the $d2 as a first checkout 2020-11-19 13:14

    $i = 0;
    $d1 = 0; 
    $d2 = 1;
    $hours = 0;
   foreach($activities as $ibd){

        $date1 = $aActivities[$d1]->start;
        $date2 = $aActivities[$d2]->end;

        //Convert tot timestamp
        $timestamp1 = strtotime($date1);
        $timestamp2 = strtotime($date2);


        //That's the formula where we can now the range between two dates in seconds
        $sum = abs((int)$timestamp2 - (int)$timestamp1)/3600; 
       
        //Sum that for the next
        $hours = $hours + $sum;

        //Move to the next checkin/checkout in the array $activities
        $d1 = $d1 + 2;
        $d2 = $d2 + 2;
        $i++;
    }

    //Return in hours
    return $hours;
}

因为我们有像 5.88 这样的小时浮点数，所以我们必须转换为小时和分钟，我们可以这样做：

 <?php echo sprintf('%02d:%02d', (int) $time, fmod($time, 1) * 60); ?>

感谢大家！

如何将不同项目的小时和分钟相加checkin/checkout

How to sum the hours and minutes with different items checkin/checkout

php

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