如何使用 Kivy 中的按钮在另一个屏幕中创建标签

Question

我遇到了一个小问题，我试图在按下 MenuScreen 中的按钮时在 LabelScreen 中创建标签。我设法做的最接近的事情是让标签出现在与按钮相同的屏幕上。

下面的代码只是我想要实现的一个简单示例。任何帮助总是感激！

.py

from kivy.app import App
from kivy.uix.floatlayout import FloatLayout
from kivy.uix.label import Label
from kivy.uix.button import Button,ButtonBehavior
from kivy.uix.image import Image
from kivy.uix.screenmanager import Screen, ScreenManager
from kivy.uix.popup import Popup
from kivy.core.window import Window
from kivy.properties import ObjectProperty, NumericProperty

class MenuScreen(Screen):
    def Item1(self,button):
        App.get_running_app().cart += 5
        label1 = Label(text="Item 1: ", font_size=25)
        self.add_widget(label1)

class LabelScreen(Screen):
    pass

class WindowManager(ScreenManager):
    pass

class ExampleApp(App):
    cart = NumericProperty(0)
    def build(self):
        return WindowManager()

if __name__ == "__main__":
    ExampleApp().run()

.kv

#:import SlideTransition kivy.uix.screenmanager.SlideTransition

<WindowManager>:
    MenuScreen:
    LabelScreen:

<MenuScreen>:
    name: "menu"

    FloatLayout:
        Button:
            text: "Add to cart"
            size_hint: 0.5,0.05
            pos_hint: {"x": 0.25, "y": 0.25}
            on_release:
                root.Item1(self)
        Label:
            text: "Cart: " + str(app.cart)
            font_size: 25
            pos_hint: {"x": 0.25, "y": 0.25}
        Button:
            text: "Label Screen"
            size_hint: 0.5,0.05
            pos_hint: {"x": 0.25, "y": 0.1}
            on_release:
                app.root.transition = SlideTransition(direction = "left")
                app.root.current = "label"

<LabelScreen>:
    name: "label"

    FloatLayout:
        Label:
            text: "I want Item1 Label to appear here \n instead of in the MenuScreen"
            font_size: 25
            pos_hint: {"x": 0, "y": 0.25}
        Button:
            text: "Back"
            size_hint: 0.5,0.05
            pos_hint: {"x": 0.25, "y": 0.1}
            on_release:
                app.root.transition = SlideTransition(direction = "right")
                app.root.current = "menu"

Answer 1

您必须参考正确的屏幕 window 您想要添加 wiget。

由于您要在 python class 中添加小部件，因此我们首先必须获取应用程序运行，然后我们才能导航到我们想要的屏幕：

def Item1(self,button):
    App.get_running_app().cart += 5
    label1 = Label(text="Item 1: ", font_size=25)

    app_running = App.get_running_app()
    root_screen = app_running.root
    label_screen = root_scren.get_screen('label')
    label_screen.add_widget(label1)

    # Or simply:
    # App.get_running_app().root.get_screen('label').add_widget(label1)

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