每次满足条件语句时如何打印列表的一个（不同）部分？

Question

所以我有一个功能，基本上是提示用户找到某个预定数字（76/七十六）。每次做出不正确的猜测时，他们都会得到提示，然后可以选择再次猜测。对于每个错误的猜测，我希望能够从我的列表中为他们提供不同的提示。这也很棘手，因为我必须有一定数量的提示，所以在列表用完后，应该提示用户在没有指导的情况下再次猜测。我还没有想出我的提示，但这是代码：

hint_list = ['filler_1','filler_2', 'filler_3', 'filler_4', 'filler_5']

def try_and_respond():
    guess = raw_input('Guess: ')
    if guess.isdigit():
        guess = int(guess)
        correct = guess == 76
    else:
        correct = guess.lower() == 'seventy-six'
    if correct:
        print '\n3[1;36;40m Fantastic! 76 is correct.'
    elif not correct:
        print '\n3[1;31;40mIncorrect. Here is a hint: 3[1;30;47m'
        print hint_list[0]
        try_and_respond()

Answer 1

保留一个计数器来决定接下来显示哪个提示。

如果你想获得随机顺序的提示，请使用 random.shuffle()

# import random  # uncomment if random hint order
hint_list = ['filler_1','filler_2', 'filler_3', 'filler_4', 'filler_5']

# uncomment next line for random hint order
# random.shuffle(hint_list)

incorrect_count = 0
def try_and_respond():
    global incorrect_count
    guess = raw_input('Guess: ')
    if guess.isdigit():
        guess = int(guess)
        correct = guess == 76
    else:
        correct = guess.lower() == 'seventy-six'
    if correct:
        print '\n3[1;36;40m Fantastic! 76 is correct.'
    else:
        if incorrect_count < len(hint_list):
            print '\n3[1;31;40mIncorrect. Here is a hint: 3[1;30;47m'
            print hint_list[incorrect_count]
            incorrect_count += 1
        try_and_respond()

try_and_respond()

这里是一个没有递归的修改版本，而是一个显式循环和一些使代码 python3 兼容的代码，但让它仍然运行与 python2

# import random  # uncomment if random hint order
import sys

# It's 2020, So I suggest to
# make the code also python 3 compatible.
if sys.version_info[0] < 3:
    input = raw_input

hint_list = ['filler_1','filler_2', 'filler_3', 'filler_4', 'filler_5']

# uncomment next line for random hint order
# random.shuffle(hint_list)

incorrect_count = 0
def try_and_respond():
    global incorrect_count
    guess = input('Guess: ')
    if guess.isdigit():
        guess = int(guess)
        correct = guess == 76
    else:
        correct = guess.lower() == 'seventy-six'
    if correct:
        print('\n3[1;36;40m Fantastic! 76 is correct.')
    else:
        if incorrect_count < len(hint_list):
            print('\n3[1;31;40mIncorrect. Here is a hint: 3[1;30;47m')
            print(hint_list[incorrect_count])
            incorrect_count += 1
    return correct

while not try_and_respond():
    try_and_respond()

Answer 2

要循环一组值，通常很容易使用模 % 运算符。

尝试以下操作：

hint_idx = 0
while True:
    print(hints[hint_idx])
    hint_idx = (hint_idx + 1) % len(hints)

每次满足条件语句时如何打印列表的一个（不同）部分？

How can I print one (different) part of a list every time a conditional statement is met?

python

loops

list

python-2.7