如何根据 sql 中的状态 ID 获取数据计数

Question

 i have following table
 
    id  statusid
    100   1
    100   2
    100   3
    101   1
    101   3 

  i am getting the result like following  

id    data1 data2 data3
100    1     1     1
101    1     0     1

但我想要如下结果

id    data1 data2+data3
100    1     2
101    1     1

我正在使用以下查询：

select id, SUM(CASE WHEN statusid=1 THEN 1 ELSE 0 END) AS data1,
SUM(CASE WHEN statusid=2 THEN 1 ELSE 0 END) AS data2,
SUM(CASE WHEN statusid=3 THEN 1 ELSE 0 END) AS data3
from employee
group by id

任何帮助。

谢谢。苏达

Answer 1

您可以像这样一起计算状态 2 和 3：

select id, 
    sum(case when statusid = 1 then 1 else 0 end) as data1,
    sum(case when statusid in (2, 3) then 1 else 0 end) as data2_3
from employee
group by id

Answer 2

您可以使用 PIVOT 子句来获得所需的结果。

使用DECODE映射状态，使2和3产生相同的值

with tab2 as (select 
id, decode(status_id,3,2,status_id) status_id2
from tab)
select * from tab2
PIVOT (count(*) "CNT"  for status_id2 in 
(1 as "DATA_1",
 2 as "DATA_2_3")
)

        ID DATA_1_CNT DATA_2_3_CNT
---------- ---------- ------------
       100          1            2
       101          1            1

如何根据 sql 中的状态 ID 获取数据计数

how to get the count of data based on status id in sql

sql

oracle

pivot

count

aggregate-functions