如何检查 Swift 中的整数是否在千位范围内？

Question

在一个循环中，我需要检查 n 索引是否是千位范围内的数字：

0...1000

1001...2000

2001...3000

and so on

我该怎么做而不是手动定义一个范围？

Answer 1

为了得到数字的范围，我把数字除以1000，根据结果求范围

let inputNumber = 6598

let dividedNumber: Float = Float(inputNumber) / 1000.0

if dividedNumber.rounded(.up) == dividedNumber.rounded(.down){
    //number is integer
    let end: Int = Int(dividedNumber.rounded(.down) * 1000)
    let start: Int = end - 1000
    print("Range is integer : ", (start + 1)...end)
    
} else {
    //number is not integer
    let start: Int = Int(dividedNumber.rounded(.down) * 1000)
    let end: Int = Int(start + 1000)
    print("Range is not integer : ", (start + 1)...end )
}

Answer 2

此功能将帮助您检查您的号码是否在千位范围内

func checkNumberRange(withNumber myNumber: Double) {
   
//    let reminder = myNumber.truncatingRemainder(dividingBy: 1) // if you wanna get reminder "Floating point"
   
    let start = floor(myNumber)
    let end = round(myNumber) + 1000
    if ((myNumber / 1000 >= 1) && (myNumber / 1000 <= 1000)) {
        print("range from \(start)...\(end)")
    }
    else {
        print("your number isn't in thousands range")
    }
    
}

checkNumberRange(withNumber: 10000067) //your number isn't in thousands range
checkNumberRange(withNumber: 12458.8) //range from 12458.0...13459.0
checkNumberRange(withNumber: 999) //your number isn't in thousands range
checkNumberRange(withNumber: 1000) //range from 1000.0...2000.0

希望对你有所帮助

如何检查 Swift 中的整数是否在千位范围内？

How to check in Swift an integer is in range of thousands?

logic

swift