Python 如何从我的打印结果中删除前导字符 return？

Question

我有以下循环遍历列表的代码。它还使用 eval 函数从列表中添加、移除和删除。如何从我的打印结果中删除前导字符 return？不尾随回车 returns.

if __name__ == '__main__':
    N = int(12)
    O = ["insert 0 5",
        "insert 1 10",
        "insert 0 6",
        "print",
        "remove 6",
        "append 9",
        "append 1",
        "sort",
        "print",
        "pop",
        "reverse",
        "print"]
    J = []
    p = []
    for i in range(0, N, 1):
        K = O[i]
        if K.lstrip("\n").find(" ") > 0:
            AK = K[0:K.find(" ")] + \
                "(" + str(K[K.find(" ")+1:]).replace(" ", ",") + ")"
        else:
            AK = K + "()"
        try:
            eval("p."+AK.lstrip("\n"))
        except (NameError, AttributeError):
            eval(AK.lstrip("\n"))
            print(p, sep="", end="")
OutPut below:

Answer 1

您的行 AK=K+'()' 正在执行 print() 命令。列表中没有 p.print() 之类的东西，这就是为什么它引发异常并且 eval(AK.lstrip("\n")) 移动到新行的原因。

编辑：按需代码：

if __name__ == '__main__':
    N = int(12)
    O = ["insert 0 5",
         "insert 1 10",
         "insert 0 6",
         "print",
         "remove 6",
         "append 9",
         "append 1",
         "sort",
         "print",
         "pop",
         "reverse",
         "print"]
    J = []
    p = []
    for i in range(0, N, 1):
        K = O[i]
        if K.lstrip("\n").find(" ") > 0:
            AK = K[0:K.find(" ")] + \
                "(" + str(K[K.find(" ")+1:]).replace(" ", ",") + ")"
        else:
            if K=="print": AK=K
            else: AK = K + "()"
        try:
            if AK=="print": eval(f"{AK}({p})")
            else: eval("p."+AK.lstrip("\n"))
        except (NameError, AttributeError):
            print("something wrong")

#Output
[6, 5, 10]
[1, 5, 9, 10]
[9, 5, 1]

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python-3.8