MySQL select 来自 table 的值,并根据第一个 table 的值对另一个 table 的值求和
MySQL select a value from a table and sum values on another table based on the value from the first table
我有两个表,users 和 sales。我希望能够得到每个用户所赚取的所有利润的总和。
Users
_ _ _ _ _ _ _ _ _ _
|id |
|first_name |
|second_name |
| |
| |
| |
| |
_ _ _ _ _ _ _ _ _ _
Sales
_ _ _ _ _ _ _ _ _ _
|id |
|user |
|profit |
| |
| |
| |
| |
_ _ _ _ _ _ _ _ _ _
一个选项使用相关子查询:
select u.*,
(select sum(s.profit) from sales s where s.user = u.id) as total_sales
from users u
尝试
SELECT
u.second_name,
u.first_name,
SUM(s.profit)
FROM
sales AS s
JOIN
users AS u ON u.id = s.user
GROUP BY
u.id
我有两个表,users 和 sales。我希望能够得到每个用户所赚取的所有利润的总和。
Users
_ _ _ _ _ _ _ _ _ _
|id |
|first_name |
|second_name |
| |
| |
| |
| |
_ _ _ _ _ _ _ _ _ _
Sales
_ _ _ _ _ _ _ _ _ _
|id |
|user |
|profit |
| |
| |
| |
| |
_ _ _ _ _ _ _ _ _ _
一个选项使用相关子查询:
select u.*,
(select sum(s.profit) from sales s where s.user = u.id) as total_sales
from users u
尝试
SELECT
u.second_name,
u.first_name,
SUM(s.profit)
FROM
sales AS s
JOIN
users AS u ON u.id = s.user
GROUP BY
u.id