如何使用我自己的值和频率在 python 中创建直方图而不使用 bin
how to create a histogram in python using my own values and frequencies witthout bins
如何使用我自己的频率在 python 上创建直方图，当我使用 bins 时，它会给我另一个值：
我在 0 和 1 之间有 1000 个数字，例如，我有 63 个数字在 [0, 0.05[ 但在直方图中我希望频率为 0.063 所有频率除以 1000
Frequencies =[0.063,0.047,0.049,0.051,0.049,0.045,0.033,0.055,0.047,0.052,0.048,0.067,0.033,0.056,0.055,0.041,0.048,0.05,0.072,0.039]
Intervals = [0 , 0.05 , 0.1 , 0.15 , 0.2 , 0.25 , 0.3 , 0.35 , 0.4 , 0.45 , 0.5 , 0.55 , 0.6 , 0.65 , 0.7, 0.75 ,0.8 , 0.85, 0.9 , 0.95, 1]
我需要绘制一个直方图，例如对于区间 [0, 0.05[，高度将为 0.063
我试过了
plt.hist(Frequencies , bins = Intervals)
但是结果是错误的
您已经有了频率，所以您不需要 plt.hist，只需 plt.bar:
x = range(len(Frequencies))
plt.bar(x, Frequencies)
tick_labels = [f'[{Intervals[i]},{Intervals[i+1]}[' for i in range(len(Intervals)-1)]
plt.xticks(x, tick_labels, rotation='vertical')
如何使用我自己的频率在 python 上创建直方图，当我使用 bins 时，它会给我另一个值： 我在 0 和 1 之间有 1000 个数字，例如，我有 63 个数字在 [0, 0.05[ 但在直方图中我希望频率为 0.063 所有频率除以 1000
Frequencies =[0.063,0.047,0.049,0.051,0.049,0.045,0.033,0.055,0.047,0.052,0.048,0.067,0.033,0.056,0.055,0.041,0.048,0.05,0.072,0.039]
Intervals = [0 , 0.05 , 0.1 , 0.15 , 0.2 , 0.25 , 0.3 , 0.35 , 0.4 , 0.45 , 0.5 , 0.55 , 0.6 , 0.65 , 0.7, 0.75 ,0.8 , 0.85, 0.9 , 0.95, 1]
我需要绘制一个直方图，例如对于区间 [0, 0.05[，高度将为 0.063 我试过了
plt.hist(Frequencies , bins = Intervals)
但是结果是错误的
您已经有了频率，所以您不需要 plt.hist，只需 plt.bar:
x = range(len(Frequencies))
plt.bar(x, Frequencies)
tick_labels = [f'[{Intervals[i]},{Intervals[i+1]}[' for i in range(len(Intervals)-1)]
plt.xticks(x, tick_labels, rotation='vertical')