如何使用 selenium 和 python 查找 aria-label

Question

这是我的代码-->

element = driver.find_elements_by_css_selector("[aria-label='收回讚']")

它不起作用，它创建了一个 None 类型。任何帮助表示赞赏！提前致谢！

更新：

我的更新码：

try:
     element = WebDriverWait(driver, 5).until(EC.visibility_of_element_located((By.XPATH, "//*[aria-label='收回讚']")))
     #check if unlike path exisit
  

except:
    element = WebDriverWait(driver, 5).until(EC.visibility_of_element_located((By.XPATH, "//*[aria-label='讚']")))
    element.click()
    #if not find like path and click it

Answer 1

找到需要归纳的元素WebDriverWait for the visibility_of_element_located() and you can use either of the following :

使用CSS_SELECTOR:

element = WebDriverWait(driver, 20).until(EC.visibility_of_element_located((By.CSS_SELECTOR, "[aria-label='收回讚']")))

使用XPATH:

element = WebDriverWait(driver, 20).until(EC.visibility_of_element_located((By.XPATH, "//*[@aria-label='收回讚']")))

注意：您必须添加以下导入：

from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC

参考资料

您可以在以下位置找到一些相关的详细说明：

如何使用 selenium 和 python 查找 aria-label

How to do find aria-label using selenium and python

python

selenium

xpath

css-selectors

webdriverwait

参考资料