来自另一个 class 的 Flutter Call Listener

Flutter Call Listener from another class

我是 Flutter 的新手(来自 Java),正在完成第一个 Android 应用程序。

在我的项目中,我使用不同的 class 来创建一个可重复使用的小部件(来自示例 here),它适用于所有方法,但我想不出一个定义和重用方法 onEditingComplete.

的方法

这是我的代码:

class AppTextField extends StatelessWidget {
  //
  AppTextField({
    this.controller,
    this.textInputType,
    this.pwValidator,

    this.editingComplete,  // this the method that is causing the problem
  });

  final TextEditingController controller;
  final TextInputType textInputType;
  final FormFieldValidator pwValidator;

  final Listener editingComplete;  //  This doesn't work. Am I using the wrong listener?

  @override
  Widget build(BuildContext context) {
    return Container(
      child: Theme(
        data: ThemeData(
          primaryColorDark: Colors.blue,
        ),
        child: Padding(
          padding: EdgeInsets.fromLTRB(25, 15, 25, 0),
          child: TextFormField(
            controller: controller,
            keyboardType: null == textInputType ? textInputType : textInputType,
            validator: null == pwValidator ? pwValidator : pwValidator,

            // I am facing problems with this line of code 
            onEditingComplete:  null == editingComplete ? editingComplete : editingComplete,                
          ),
        ),
      ),
    );
  }
}

这是 class 我想实现和重用小部件的地方 :

Container(
    child: AppTextField(

          controller: _controllerPassword,              
          pwValidator: (value) { },
          
          onEditingComplete:          // here is where I am facing difficulties              
    ),

属性 onEditingComplete is a VoidCallback。这是一个没有参数的函数,不 return 任何数据。

AppTextField中定义onEditingComplete

final VoidCallback onEditingComplete;

然后赋给TextFormField的onEditingComplete属性。另外,去掉三元运算符。

onEditingComplete: onEditingComplete

并且在使用小部件时,像这样传递回调:

Container(
  child: AppTextField(

      controller: _controllerPassword,              
      pwValidator: (value) { },
      
      onEditingComplete:   (){
          //Do what you want to do here.
      }           
),