Idgenerator laravel 8，如何修复异常 "table field type is bigint but prefix is string"

Question

为什么总是出现这条信息？即使我想制作一个带有 2 个点的 id = 190772.2021.00000001 无法添加“.” （点）那样只能加1个点 1907722021.00000001 factory.php


namespace Database\Factories;

use App\Models\Anggota;
use Illuminate\Database\Eloquent\Factories\Factory;
use App\Models\User;
use Haruncpi\LaravelIdGenerator\IdGenerator;

class AnggotaFactory extends Factory
{
    /**
     * The name of the factory's corresponding model.
     *
     * @var string
     */
    protected $model = Anggota::class;

    /**
     * Define the model's default state.
     *
     * @return array
     */
    public function definition()
    {
        $tgl = $this->faker->date;

        return [
            'id_user' => User::factory(),
            'no_anggota' => IdGenerator::generate([
                    'table' => 'anggotas', 
                    'length' => 19, 
                    'prefix' => date('dmy', strtotime($tgl)).date('.Y.')
                ]),
            'nama_lengkap' => $this->faker->name,
            'tempat_lahir' => $this->faker->cityPrefix,
            'tanggal_lahir' => $tgl,
            'nama_instansi' => $this->faker->word,
        ];
    }
}

文件迁移


use Illuminate\Database\Migrations\Migration;
use Illuminate\Database\Schema\Blueprint;
use Illuminate\Support\Facades\Schema;

class CreateAnggotasTable extends Migration
{
    /**
     * Run the migrations.
     *
     * @return void
     */
    public function up()
    {
        Schema::create('anggotas', function (Blueprint $table) {
            $table->id();
            $table->unsignedBigInteger('id_user')->unique();
            $table->string('no_anggota');
            $table->string('nama_lengkap');
            $table->string('tempat_lahir');
            $table->date('tanggal_lahir');
            $table->string('nama_instansi');
            $table->timestamps();
        });
    }

    /**
     * Reverse the migrations.
     *
     * @return void
     */
    public function down()
    {
        Schema::dropIfExists('anggotas');
    }
}

而模式数据库中的列“no_anggota”的类型为“字符串”，但出现“table 字段类型为 bigint 但前缀为字符串”

如何求解使得结果=190772.2021.00000001

帮帮我，谢谢

Answer 1

laravel ID generator package by default use table's id column. According to your need, the documentation says (example 4)，你也要通过field

您需要的输出：190772.2021.00000001（长度为 20，带两个点）

解决方案: 只需通过'field' => 'no_anggota'和'length' => 20

$tgl = $this->faker->date;

$idConfig = [
    'table' => 'anggotas',
    'field' => 'no_anggota',
    'length' => 20,
    'prefix' => date('dmy', strtotime($tgl)).date('.Y.')
];

return [
    'id_user' => User::factory(),
    'no_anggota' => IdGenerator::generate($idConfig),
    'nama_lengkap' => $this->faker->name,
    'tempat_lahir' => $this->faker->cityPrefix,
    'tanggal_lahir' => $tgl,
    'nama_instansi' => $this->faker->word,
];

Idgenerator laravel 8，如何修复异常 "table field type is bigint but prefix is string"

Idgenerator laravel 8, how to fix Exception "table field type is bigint but prefix is string"

php

laravel

eloquent

laravel-8