TypeError: __init__() got an unexpected keyword argument 'restrict_xpath'

Question

我是 scrapy 的新手，在尝试 运行 我的蜘蛛时遇到了以下问题。© 阅读了很多有关规则 class 的内容，但仍然无法找出错误。我错过了什么，是因为回调参数的语法

代码如下：

import scrapy
from scrapy.linkextractors import LinkExtractor
from scrapy.spiders import CrawlSpider, Rule


class ParserSpider(CrawlSpider):
    name = 'parser'
    allowed_domains = ['eksisozluk.com/']
    start_urls = ['https://eksisozluk.com//']

    rules = (
        Rule(LinkExtractor(restrict_xpath='//div[@id="mobile-index"]/ul/li'),callback='parse_item', follow=True),
        Rule(LinkExtractor(restrict_xpath='//div[@id="topic"]/div[1]/div[2]/a[2]'))
    )

    def parse_item(self, response):
        yield {
            'title': response.xpath("//h1[@id='title']/text()").get(),
            'entry': response.xpath("//div[@class='content']text()").get(),
            'yazar': response.xpath("//a[@class='entry-author']/text()").get(),
            'title': response.xpath("//a[@class='entry-date permalink']/text()").get(),

        }

并输出：

 File "/home/bodhi/Desktop/scrape_projects/eksi_parser/eksi_parser/spiders/parser.py", line 6, in <module>
    class ParserSpider(CrawlSpider):
  File "/home/bodhi/Desktop/scrape_projects/eksi_parser/eksi_parser/spiders/parser.py", line 12, in ParserSpider
    Rule(LinkExtractor(restrict_xpath='//div[@id="mobile-index"]/ul/li'),callback='parse_item', follow=True),
TypeError: __init__() got an unexpected keyword argument 'restrict_xpath'

Answer 1

正确的参数是 restrict_xpaths，s 而不是 restrict_xpath。