累积数据连同原始数据

Question

我有两个 tables .

输入：

我加入了日历table并将数据更新到最新。

我需要一个输出。

我尝试使用 UNION 和聚合进行查询，但我需要查询两次并聚合相同的结果 table。由于 table 非常大。是否可以选择不同的方式

SELECT ID ,PERIOD,SUM(AMOUNTYTD) AMOUNTYTD,SUM(AMOUNT) AMOUNT
FROM (
            SELECT ID ,b.PERIOD,SUM(AMOUNT) AMOUNTYTD,0 AMOUNT
            FROM transaction a RIGHT OUTER JOIN CALENDAR b
            ON b.PERIOD<=a.PERIOD
            UNION ALL
            SELECT ID ,PERIOD,0,SUM(AMOUNT)
            FROM transaction
            GROUP BY ID,PERIOD
    )
GROUP BY ID,PERIOD

Answer 1

将定期金额与累计金额并排显示很容易 - 实际上，您只需要能够使用定期金额创建正确的 table，累计金额是分析求和的简单应用.

将日历 table 连接到“输入”数据的关键是使用 partitioned 外部连接 - 注意 partition by (id) 中的子句加入两个 table。这导致“输入”数据被划分为单独的子tables，每个不同的id；日历 table 的外部连接是针对每个这样的子 table 单独完成的，然后结果与逻辑“联合所有”相结合。

with
  input (id, period, amount) as (
    select 1, 202010, 100 from dual union all
    select 1, 202011,  50 from dual union all
    select 2, 202011, 400 from dual
  )
, calendar (period) as (
    select 202010 from dual union all
    select 202011 from dual union all
    select 202012 from dual union all
    select 202101 from dual
  )
select id, period, amountytd, amount
from   (
         select i.id, period, i.amount, 
                sum(i.amount) over (partition by i.id order by period)
                  as amountytd
         from   calendar c left outer join input i partition by (id)
                           using (period)
       )
where  amountytd is not null
order  by id, period
;

 ID     PERIOD  AMOUNTYTD     AMOUNT
--- ---------- ---------- ----------
  1     202010        100        100
  1     202011        150         50
  1     202012        150           
  1     202101        150           
  2     202011        400        400
  2     202012        400           
  2     202101        400

Answer 2

您有查询 - I have joined with the calendar table and bring the data till current. 让我们假设它是 your_query

您可以在其上使用分析函数，如下所示：

Select t.*,
       Case when lead(amountytd) over (partition by id order by period) = amountytd 
            then null 
            else amountytd
       end as amount
  From (your_query) t

累积数据连同原始数据

Cumulative data along with the original data

sql

oracle

oracle11g