JavaScript Array of Arrays: 想要获取值为 'PROCESSED' 的第一行

Question

我如何 return 只有第一个通过条件的值，其中值为以下数组中的“PROCESSED”？

[
  [ '21/01/2021 11:11:57', '111', 'IN PROGRESS' ],
  [ '21/01/2021 11:09:07', '222', 'PROCESSED' ],
  [ '21/01/2021 11:08:57', '333', 'PROCESSED' ],
  [ '21/01/2021 11:08:57', '444', 'PROCESSED' ],
  [ '21/01/2021 11:07:25', '555', 'PROCESSED' ],
]

我想return原始数组中的整行和索引。

Answer 1

试试这个：

const data = [
  ["21/01/2021 11:11:57", "111", "IN PROGRESS"],
  ["21/01/2021 11:09:07", "222", "PROCESSED"],
  ["21/01/2021 11:08:57", "333", "PROCESSED"],
  ["21/01/2021 11:08:57", "444", "PROCESSED"],
  ["21/01/2021 11:07:25", "555", "PROCESSED"],
];

const result = data.filter((item) => item[2] === "PROCESSED")[0];

console.log(result);

Answer 2

您可以使用 Array#findIndex

const arr = [[ '21/01/2021 11:11:57', '111', 'IN PROGRESS' ], [ '21/01/2021 11:09:07', '222', 'PROCESSED' ], [ '21/01/2021 11:08:57', '333', 'PROCESSED' ], [ '21/01/2021 11:08:57', '444', 'PROCESSED' ], [ '21/01/2021 11:07:25', '555', 'PROCESSED' ], ];

let ind = arr.findIndex(a=> a[2] == 'PROCESSED');

console.log(arr[ind],ind)

Answer 3

I want to return the whole row and the index in the original array.

根据需要索引，可以使用.findIndex() with a combination of destructuring assignment 从数组中提取第二个索引([,,status]) 处的字符串。然后可以对第二个索引为 'PROCESSED' 的第一项 return true 来获取索引。一旦你有了索引，你就可以抓取行（即：索引处的内部数组）：

const arr = [ [ '21/01/2021 11:11:57', '111', 'IN PROGRESS' ], [ '21/01/2021 11:09:07', '222', 'PROCESSED' ], [ '21/01/2021 11:08:57', '333', 'PROCESSED' ], [ '21/01/2021 11:08:57', '444', 'PROCESSED' ], [ '21/01/2021 11:07:25', '555', 'PROCESSED' ], ];

const idx = arr.findIndex(([,,status]) => status === "PROCESSED");
const row = arr[idx];
console.log(idx, row);

JavaScript Array of Arrays: 想要获取值为 'PROCESSED' 的第一行

JavaScript Array of Arrays: want to get the first row where the value is 'PROCESSED'

javascript

arrays

filter

find