如何访问其中包含空格的对象变量？打字稿

Question

所以我有一个传入对象，如下所示：

Email: "edwardmuldrew@gmail.com"
ID: "106150111352875619571"
Image URL: "https://lh3.googleusercontent.com/a-/AOh14Gi8zfXDXbMG_kvgmIs2yYiAGbuplyapc0gyjXqpTA=s96-c"
Name: "Edward Muldrew"

我尝试映射到我的对象 User

export class User {
    constructor(
        public ID: string,
        public Name: string,
        public Image_URL: string,
        public Email: string,
    ) { }
}
      

      var obj = localStorage.getItem('user') || '{}';
      this.user = JSON.parse(obj);

除了图像 URL link 之外的所有内容都很好，因为该变量中有一个 space。这是一个打字稿文件，我不确定如何访问它。我试过使用

obj['Image URL']

但这并没有奏效。还有其他解决方案吗？

Answer 1

这里有：

const obj = {
  Email: "edwardmuldrew@gmail.com",
  ID: "106150111352875619571",
  ['Image URL']: "https://lh3.googleusercontent.com/a-/AOh14Gi8zfXDXbMG_kvgmIs2yYiAGbuplyapc0gyjXqpTA=s96-c",
  Name: "Edward Muldrew",

}

type Obj = typeof obj

export class User implements Obj {
  public ID: string;
  public Name: string;
  public ['Image URL']: string;
  public Email: string;
  constructor(
    id: string,
    name: string,
    imageUrl: string,
    email: string,

  ) {
    this.ID = id;
    this.Name = name;
    this['Image URL'] = imageUrl;
    this.Email = email

  }
}

const foo = new User('1', 'John', 'http://example.com/data/index.png', 'sdf@gmai.com')
var result = foo['Image URL'] // string

如何访问其中包含空格的对象变量？打字稿

How to access object variable with spaces in it? Typescript

mapping

typescript