从 case 语句 oracle sql 中按 Count 捕获条件语句组

Question

您好，我正在尝试按组捕获计数，但我需要的组来自案例陈述中的人工列，我想知道如何实现这一点，下面是我正在使用的 sql 代码这可能使用 WITH CTE 吗？或者有没有任何最简单的方法，下面是查询以及现有结果和预期结果

db - Oracle 数据库 11g

查询

SELECT DISTINCT
EA.TGT_TBL,
REGEXP_SUBSTR(EA.TGT_TBL, '[0-9]+') AS SYSTEM_ID,
COUNT(*),
ROUND(100*RATIO_TO_REPORT(COUNT(*)) OVER (), 2) PERCENTAGE,
CASE WHEN EA.TGT_TBL LIKE '%DWH_STAGE.%' THEN 'STAGE'
     WHEN EA.TGT_TBL LIKE '%DWH_STAGE_CST.%'THEN 'STAGE'
     WHEN EA.TGT_TBL LIKE 'DEV_DWH.%' THEN 'STAGE'
     WHEN EA.TGT_TBL LIKE 'BI_EDW.%' THEN 'EDW'
     WHEN EA.TGT_TBL LIKE 'DEV_DWH_EDW.%' THEN 'EDW'
     WHEN EA.TGT_TBL LIKE 'BI_EDW_CST.%' THEN 'EDW'
     WHEN EA.TGT_TBL LIKE 'DEV_DWH_EDW_CST.%' THEN 'EDW'
     WHEN EA.TGT_TBL LIKE 'BI_EDW_PREM2.%' THEN 'EDW'
     WHEN EA.TGT_TBL LIKE 'DEV_DWH_EDW.%' THEN 'EDW'
     WHEN EA.TGT_TBL LIKE 'BI_MART.%' THEN 'MART'
     WHEN EA.TGT_TBL LIKE 'DEV_DWH_MART.%' THEN 'MART'
     WHEN EA.TGT_TBL LIKE 'BI_MART_CST.%' THEN 'MART'
     WHEN EA.TGT_TBL LIKE 'DEV_DWH_MART_CST.%' THEN 'MART'
     WHEN EA.TGT_TBL LIKE 'SHP_MART.%' THEN 'MART'
     WHEN EA.TGT_TBL LIKE 'BI_REPO.%' THEN 'REPO'
     WHEN EA.TGT_TBL LIKE 'BI_PMART.%' THEN 'MART'
     WHEN EA.TGT_TBL LIKE 'BI_META.%' THEN 'META'
     WHEN EA.TGT_TBL LIKE 'BI_META_CST.%' THEN 'META'
     WHEN EA.TGT_TBL LIKE 'DEV_DWH_META.%' THEN 'META'
     WHEN EA.TGT_TBL LIKE 'BI_DFL.%' THEN 'DFL'
     WHEN EA.TGT_TBL LIKE 'MPN_ETL_WORK.%' THEN 'VISA'
ELSE 'OTHER'
    END AS SCHEMA_GROUP
FROM BI_ETL_AUD EA
WHERE 1=1
AND TRUNC(EA.SESS_BEG)=TRUNC(SYSDATE)
AND TRUNC(EA.SESS_END)=TRUNC(SYSDATE)
GROUP BY 
EA.TGT_TBL,
REGEXP_SUBSTR(EA.TGT_TBL, '[0-9]+')
ORDER BY 
EA.TGT_TBL,
REGEXP_SUBSTR(EA.TGT_TBL, '[0-9]+'),SYSTEM_ID,SCHEMA_GROUP

现有结果

TGT_TBL         SYSTEM_ID SCHEMA_GROUP COUNT(*) PERCENTAGE
AB_01_SHP_ORDER 01        STAGE        10       0.1
BC_AB_PUR_STTS  null      EDW          200      2
GH_FND_AJD_DAA  null      MART         10       0.1
SD_HS_HHA_DHD   null      REPO         100      1

预期结果

SCHEMA_GROUP COUNT(*) PERCENTAGE
STAGE        500      10
EDW          1500     30
MART         3000     60
REPO         250      05

请注意，我正在尝试从 SCHEMA_GROUP 获取组（此列不在 table - CASE 语句中使用的人工列）

Answer 1

这是使用 CTE 进行设置的方法（有一点限制 case）

with ea as (
select 
CASE WHEN EA.TGT_TBL LIKE '%DWH_STAGE.%' THEN 'STAGE'
-- cur for brevity
     WHEN EA.TGT_TBL LIKE 'MPN_ETL_WORK.%' THEN 'VISA'
ELSE 'OTHER'
    END AS SCHEMA_GROUP
FROM BI_ETL_AUD EA)
select 
  SCHEMA_GROUP,
  COUNT(*),
  ROUND(100*RATIO_TO_REPORT(COUNT(*)) OVER (), 2) PERCENTAGE
from ea
group by SCHEMA_GROUP;

这会产生

SCHEM   COUNT(*) PERCENTAGE
----- ---------- ----------
OTHER          3         75
VISA           1         25

带有示例数据

create table BI_ETL_AUD as
select 'DEV_DWH_EDW.'  TGT_TBL from dual union all
select 'DEV_DWH_EDW.'  TGT_TBL from dual union all
select 'DEV_DWH_EDW.'  TGT_TBL from dual union all
select 'MPN_ETL_WORK.'  TGT_TBL from dual

或者您始终可以使用单个查询，您需要在 GROUP BY 列中 准确且不带别名 复制大小写：

select 
  CASE WHEN EA.TGT_TBL LIKE '%DWH_STAGE.%' THEN 'STAGE'
  -- cur for brevity
     WHEN EA.TGT_TBL LIKE 'MPN_ETL_WORK.%' THEN 'VISA'
  ELSE 'OTHER'
    END AS SCHEMA_GROUP,
  COUNT(*),
  ROUND(100*RATIO_TO_REPORT(COUNT(*)) OVER (), 2) PERCENTAGE    
FROM BI_ETL_AUD EA
group by CASE WHEN EA.TGT_TBL LIKE '%DWH_STAGE.%' THEN 'STAGE'
-- cur for brevity
     WHEN EA.TGT_TBL LIKE 'MPN_ETL_WORK.%' THEN 'VISA'
ELSE 'OTHER'
    END

从 case 语句 oracle sql 中按 Count 捕获条件语句组

Capture the Conditional statement group by Count from case statement oracle sql

sql

oracle

group-by

case

conditional-statements