为什么不能在 C++ 中将 putc() 实现为宏？ （或者可以吗？）
Why can't putc() be implemented as a macro in C++? (Or can it?)
阅读 en.cppreference.com 关于 fputc()/putc() 的内容，我偶然发现了以下语句：
In C, putc() may be implemented as a macro, which is disallowed in C++.
这是真的吗？如果是这样，这是在哪里（在 C++ 标准中）声明的？
可能相关：
putc在C标准中被指定为一个函数：
7.19.7.8 The putc function
C 标准允许将任何 C 标准库函数实现为宏（仍然需要提供真正的函数实现，但如果在头文件中定义了宏，那就是将使用的）：
7.1.4 Use of library functions
Any function declared in a header may be additionally implemented as a function-like macro
但 C++ 标准明确指出这些必须定义为函数：
17.4.1.2.6 Headers
Names that are defined as functions in C shall be defined as functions in the C++ Standard Library.
脚注明确说明不允许附加宏定义：
This disallows the practice, allowed in C, of providing a "masking macro" in addition to the function prototype. The only way to achieve equivalent "inline" behavior in C++ is to provide a definition as an extern inlin
阅读 en.cppreference.com 关于 fputc()/putc() 的内容，我偶然发现了以下语句：
In C, putc() may be implemented as a macro, which is disallowed in C++.
这是真的吗？如果是这样，这是在哪里（在 C++ 标准中）声明的？
可能相关：
putc在C标准中被指定为一个函数：
7.19.7.8 The putc function
C 标准允许将任何 C 标准库函数实现为宏（仍然需要提供真正的函数实现，但如果在头文件中定义了宏，那就是将使用的）：
7.1.4 Use of library functions
Any function declared in a header may be additionally implemented as a function-like macro
但 C++ 标准明确指出这些必须定义为函数：
17.4.1.2.6 Headers
Names that are defined as functions in C shall be defined as functions in the C++ Standard Library.
脚注明确说明不允许附加宏定义：
This disallows the practice, allowed in C, of providing a "masking macro" in addition to the function prototype. The only way to achieve equivalent "inline" behavior in C++ is to provide a definition as an extern inlin