为什么显示 'list index out of range'？

Question

n = int(input())
students = list()
for i in range(0,n):
    students[i][0]=input("Name: "); students[i][1]=float(input("Grade: "))

我写了这段代码，但 'list index out of range' 正在显示。我不明白为什么会这样。

    ---------------------------------------------------------------------------
IndexError                                Traceback (most recent call last)
<ipython-input-46-966bd0f334a2> in <module>
      1 n = int(input())
      2 for i in range(0,n):
----> 3     students[i][0]=input(); students[i][1]=float(input())

IndexError: list index out of range

请帮忙。

Answer 1

您的代码不起作用的原因是您试图在 students 为空列表时分配 students[i]。同样，当 students[i] 甚至不存在时，您试图分配 students[i][0] 和 students[i][1]！

解决方案很简单：不是分配给列表 (x[1] = 3)，而是附加到列表 (x.append(3))。

n = int(input())
students = list()
for i in range(0,n):
    students.append([]) # Must add empty list otherwise students[i] doesn't exist
    students[i].append(input("Name: ")); students[i].append(float(input("Grade: ")))
    
print(students)
# Prints [['a', 1.0], ['b', 2.0], ['c', 3.0]]
# after inputting 3, a, 1, b, 2, c, 3

为什么显示 'list index out of range'？

why is 'list index out of range' showing?

python

list

range

traceback