我想在 javascript 中捕获选中复选框的所有标签
I want to catch all labels of checked checkbox in javascript
有没有办法在 Javascript(不是 JQuery)中捕获选中复选框的所有标签文本。
我的HTML是:
<div class="wpgu-onboarding-answer-container">
<div class="wpgu-onboarding-answer" data-bc-answer-post="Firstitem">
<input id="post-3-0" class="wpgu-onboarding-answer-checkbox" type="checkbox" name="posts_stijlen[]" value="670" checked="checked">
<label for="post-3-0" class="wpgu-onboarding-answer-label">
<span class="wpgu-onboarding-answer-title">Firstitem</span>
</label>
</div>
<div class="wpgu-onboarding-answer" data-bc-answer-post="SecondItem">
<input id="post-3-8" class="wpgu-onboarding-answer-checkbox" type="checkbox" name="posts_stijlen[]" value="681">
<label for="post-3-8" class="wpgu-onboarding-answer-label">
<span class="wpgu-onboarding-answer-title">SecondItem</span>
</label>
</div>
</div>
我想在 Javascript 中捕获选中复选框的标签,以便将其用作 Google Tagmanager 中的 Javascript 变量。
目前我有这段代码(来自 www.simoahava.com)来捕获选中复选框的值。
function () {
var inputs = document.querySelectorAll('.wpgu-onboarding-answer-containter input'),
selectedCheckboxes = [];
for (var i = 0; i < inputs.length; i++) {
if (inputs[i].type === "checkbox" && inputs[i].checked) {
selectedCheckboxes.push(inputs[i].value);
}
}
return selectedCheckboxes;
}
此脚本为我提供了所有值,但这些是 none-描述性值。但我想要描述性标签。
有没有办法在 class .wpgu-onboarding-answer-title 所有选中复选框的范围内捕获文本?
提前致谢
埃里克
基于 this answer 使用 jQuery,您可以使用属性选择器和要为其获取标签的元素的 ID,例如document.querySelector('label[for=' + button.id + ']')
,然后获取其textContent得到实际标签:
document.querySelectorAll('input.wpgu-onboarding-answer-checkbox').forEach(input => {
console.log(input.id + ' ' +
document.querySelector('label[for=' + input.id + ']').textContent.trim() + ' ' +
(input.checked? '' : 'not ') + 'checked'
)
});
<div class="wpgu-onboarding-answer-container">
<div class="wpgu-onboarding-answer" data-bc-answer-post="Firstitem">
<input id="post-3-0" class="wpgu-onboarding-answer-checkbox" type="checkbox" name="posts_stijlen[]" value="670" checked="checked">
<label for="post-3-0" class="wpgu-onboarding-answer-label">
<span class="wpgu-onboarding-answer-title">Firstitem</span>
</label>
</div>
<div class="wpgu-onboarding-answer" data-bc-answer-post="SecondItem">
<input id="post-3-8" class="wpgu-onboarding-answer-checkbox" type="checkbox" name="posts_stijlen[]" value="681">
<label for="post-3-8" class="wpgu-onboarding-answer-label">
<span class="wpgu-onboarding-answer-title">SecondItem</span>
</label>
</div>
</div>
除了之前的解决方案,想分享一个基于问题中提到的代码的更简单的解决方案。解决方案可以很简单,只需获取带有 class 和 wpgu-onboarding-answer-title
的所有标签,并根据选择的输入元素获取相应的标签索引并使用它。
请注意,我添加了一个额外的按钮来方便地测试功能。
function abc() {
var labels = document.querySelectorAll('.wpgu-onboarding-answer-title');
var inputs = document.querySelectorAll('.wpgu-onboarding-answer-container input'),
selectedCheckboxes = [];
for (var i = 0; i < inputs.length; i++) {
if (inputs[i].type === "checkbox" && inputs[i].checked) {
selectedCheckboxes.push(labels[i].textContent);
//selectedCheckboxes.push(inputs[i].value);
}
}
console.log(selectedCheckboxes);
return selectedCheckboxes;
}
<div class="wpgu-onboarding-answer-container">
<div class="wpgu-onboarding-answer" data-bc-answer-post="Firstitem">
<input id="post-3-0" class="wpgu-onboarding-answer-checkbox" type="checkbox" name="posts_stijlen[]" value="670" checked="checked">
<label for="post-3-0" class="wpgu-onboarding-answer-label">
<span class="wpgu-onboarding-answer-title">Firstitem</span>
</label>
</div>
<div class="wpgu-onboarding-answer" data-bc-answer-post="SecondItem">
<input id="post-3-8" class="wpgu-onboarding-answer-checkbox" type="checkbox" name="posts_stijlen[]" value="681">
<label for="post-3-8" class="wpgu-onboarding-answer-label">
<span class="wpgu-onboarding-answer-title">SecondItem</span>
</label>
</div>
</div>
<button onclick="abc()">
Fetch All Chkbox Values
</button>
请注意,此解决方案只有在您将 wpgu-onboarding-answer-title
class 仅用于此目的而不是之前页面中的其他任何地方时才有效。
这对你有帮助。
var inputs = document.querySelectorAll(".wpgu-onboarding-answer-container input:checked+label>span");
var checkbox = [];
inputs.forEach(input=>{
checkbox.push(input.textContent);
console.log(input.textContent)
});
好运!
有没有办法在 Javascript(不是 JQuery)中捕获选中复选框的所有标签文本。
我的HTML是:
<div class="wpgu-onboarding-answer-container">
<div class="wpgu-onboarding-answer" data-bc-answer-post="Firstitem">
<input id="post-3-0" class="wpgu-onboarding-answer-checkbox" type="checkbox" name="posts_stijlen[]" value="670" checked="checked">
<label for="post-3-0" class="wpgu-onboarding-answer-label">
<span class="wpgu-onboarding-answer-title">Firstitem</span>
</label>
</div>
<div class="wpgu-onboarding-answer" data-bc-answer-post="SecondItem">
<input id="post-3-8" class="wpgu-onboarding-answer-checkbox" type="checkbox" name="posts_stijlen[]" value="681">
<label for="post-3-8" class="wpgu-onboarding-answer-label">
<span class="wpgu-onboarding-answer-title">SecondItem</span>
</label>
</div>
</div>
我想在 Javascript 中捕获选中复选框的标签,以便将其用作 Google Tagmanager 中的 Javascript 变量。
目前我有这段代码(来自 www.simoahava.com)来捕获选中复选框的值。
function () {
var inputs = document.querySelectorAll('.wpgu-onboarding-answer-containter input'),
selectedCheckboxes = [];
for (var i = 0; i < inputs.length; i++) {
if (inputs[i].type === "checkbox" && inputs[i].checked) {
selectedCheckboxes.push(inputs[i].value);
}
}
return selectedCheckboxes;
}
此脚本为我提供了所有值,但这些是 none-描述性值。但我想要描述性标签。
有没有办法在 class .wpgu-onboarding-answer-title 所有选中复选框的范围内捕获文本?
提前致谢
埃里克
基于 this answer 使用 jQuery,您可以使用属性选择器和要为其获取标签的元素的 ID,例如document.querySelector('label[for=' + button.id + ']')
,然后获取其textContent得到实际标签:
document.querySelectorAll('input.wpgu-onboarding-answer-checkbox').forEach(input => {
console.log(input.id + ' ' +
document.querySelector('label[for=' + input.id + ']').textContent.trim() + ' ' +
(input.checked? '' : 'not ') + 'checked'
)
});
<div class="wpgu-onboarding-answer-container">
<div class="wpgu-onboarding-answer" data-bc-answer-post="Firstitem">
<input id="post-3-0" class="wpgu-onboarding-answer-checkbox" type="checkbox" name="posts_stijlen[]" value="670" checked="checked">
<label for="post-3-0" class="wpgu-onboarding-answer-label">
<span class="wpgu-onboarding-answer-title">Firstitem</span>
</label>
</div>
<div class="wpgu-onboarding-answer" data-bc-answer-post="SecondItem">
<input id="post-3-8" class="wpgu-onboarding-answer-checkbox" type="checkbox" name="posts_stijlen[]" value="681">
<label for="post-3-8" class="wpgu-onboarding-answer-label">
<span class="wpgu-onboarding-answer-title">SecondItem</span>
</label>
</div>
</div>
除了之前的解决方案,想分享一个基于问题中提到的代码的更简单的解决方案。解决方案可以很简单,只需获取带有 class 和 wpgu-onboarding-answer-title
的所有标签,并根据选择的输入元素获取相应的标签索引并使用它。
请注意,我添加了一个额外的按钮来方便地测试功能。
function abc() {
var labels = document.querySelectorAll('.wpgu-onboarding-answer-title');
var inputs = document.querySelectorAll('.wpgu-onboarding-answer-container input'),
selectedCheckboxes = [];
for (var i = 0; i < inputs.length; i++) {
if (inputs[i].type === "checkbox" && inputs[i].checked) {
selectedCheckboxes.push(labels[i].textContent);
//selectedCheckboxes.push(inputs[i].value);
}
}
console.log(selectedCheckboxes);
return selectedCheckboxes;
}
<div class="wpgu-onboarding-answer-container">
<div class="wpgu-onboarding-answer" data-bc-answer-post="Firstitem">
<input id="post-3-0" class="wpgu-onboarding-answer-checkbox" type="checkbox" name="posts_stijlen[]" value="670" checked="checked">
<label for="post-3-0" class="wpgu-onboarding-answer-label">
<span class="wpgu-onboarding-answer-title">Firstitem</span>
</label>
</div>
<div class="wpgu-onboarding-answer" data-bc-answer-post="SecondItem">
<input id="post-3-8" class="wpgu-onboarding-answer-checkbox" type="checkbox" name="posts_stijlen[]" value="681">
<label for="post-3-8" class="wpgu-onboarding-answer-label">
<span class="wpgu-onboarding-answer-title">SecondItem</span>
</label>
</div>
</div>
<button onclick="abc()">
Fetch All Chkbox Values
</button>
请注意,此解决方案只有在您将 wpgu-onboarding-answer-title
class 仅用于此目的而不是之前页面中的其他任何地方时才有效。
这对你有帮助。
var inputs = document.querySelectorAll(".wpgu-onboarding-answer-container input:checked+label>span");
var checkbox = [];
inputs.forEach(input=>{
checkbox.push(input.textContent);
console.log(input.textContent)
});
好运!