从 GROUP BY 操作中选择最大计数

Question

请原谅我的 SQL 知识，但我有一个 Person table 和以下数据 -

Id          Name
----        ------
1           a
2           b
3           b
4           c

我想要以下结果 -

Name      Total
------    ------
b         2

如果我使用 GROUP BY 查询 -

SELECT Name, Total=COUNT(*) FROM Person GROUP BY Name

它给了我 -

Name   Total
------ ------
a      1
b      2
c      1

但我只想要数量最多的那个。我如何获得它？

Answer 1

试试这个...

SELECT Name, COUNT(*) 
        FROM Person 
        GROUP BY Name 
        having COUNT(*)=( SELECT max(COUNT(*)) FROM Person GROUP BY Name) ;

Answer 2

答案是：

WITH MaxGroup AS (
   SELECT Name, COUNT(*) AS Total
   FROM Person
   GROUP BY Name)
SELECT Name, Total
FROM MaxGroup
WHERE Total = (SELECT MAX(Total) FROM MaxGroup)

Answer 3

在 SQL 服务器中执行此操作的最简单方法是使用 top 语法：

SELECT   TOP 1 Name, COUNT(*) AS Total 
FROM     Person 
GROUP BY Name  
ORDER BY 2 DESC

Answer 4

如果你想要领带

SELECT top (1) with ties Name, COUNT(*) AS [count]
  FROM Person 
 GROUP BY Name  
 ORDER BY count(*) DESC

从 GROUP BY 操作中选择最大计数

Selecting the maximum count from a GROUP BY operation

sql

select

group-by

max

sql-server-2008-r2