如何抓取页面标题？

Question

我不会抓取页面标题，下面是我的代码（很简单），但我不知道哪里错了，如果你有任何想法请告诉我，谢谢。

from selenium import webdriver
url="https://sukebei.nyaa.si/?s=seeders&o=desc&p=1"
driver_path = "C:\webdriver\chromedriver.exe"
option = webdriver.ChromeOptions()
driver = webdriver.Chrome(driver_path, options=option)
driver.implicitly_wait(10)
driver.get(url)
print(driver.find_element_by_xpath("/html/head/title").text)

Answer 1

from selenium import webdriver
url="https://sukebei.nyaa.si/?s=seeders&o=desc&p=1"
driver_path = "C:\webdriver\chromedriver.exe"
option = webdriver.ChromeOptions()
driver = webdriver.Chrome(driver_path, options=option)
driver.implicitly_wait(10)
driver.get(url)
print(driver.title)

Answer 2

要抓取您必须诱导的页面标题WebDriverWait for the visibility_of_element_located() for the <table> with torrent-list and you can use either of the following Locator Strategies:

使用CSS_SELECTOR:

driver.get('https://sukebei.nyaa.si/?s=seeders&o=desc&p=1')
WebDriverWait(driver, 20).until(EC.visibility_of_element_located((By.CSS_SELECTOR, "table.torrent-list")))
print(driver.title)

使用XPATH:

driver.get('https://sukebei.nyaa.si/?s=seeders&o=desc&p=1')
WebDriverWait(driver, 20).until(EC.visibility_of_element_located((By.XPATH, "//table[contains(@class, 'torrent-list')]")))
print(driver.title)

控制台输出：
```
Browse :: Sukebei
```

注意：您必须添加以下导入：

from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC

如何抓取页面标题？

How to crawl the title of the page?

python

xpath

css-selectors

selenium-webdriver

webdriverwait