如何在 Django 中获取同一作者的书籍
How to get books of the the same author in Django
我正在开发一个在线书店。
这是模型:
class Author(models.Model):
name = models.CharField(max_length=250, unique=True)
class Publisher(models.Model):
name = models.CharField(max_length=250, unique=True)
class Book(models.Model):
author = models.ManyToManyField(Author, related_name='authors')
publisher = models.ForeignKey(Publisher, on_delete=models.PROTECT, blank=True, null=True)
isbn13 = models.BigIntegerField(unique=True)
name = models.CharField(max_length=500)
...
视图如下:
class AuthorsListView(ListView):
model = Author
context_object_name = 'authors_list'
template_name = 'authors_list.html'
paginate_by = 500
class AuthorBooksListView(ListView):
model = Book
context_object_name = 'author_books'
template_name = 'author_books.html'
def get_queryset(self, **kwargs):
author_id = Author.objects.get(pk = self.kwargs['pk'])
qs = super().get_queryset(**kwargs)
return qs.filter(author = author_id)
def get_context_data(self, **kwargs):
# Call the base implementation first to get a context
context = super().get_context_data(**kwargs)
# Add in a QuerySet
context['author'] = Author.objects.get(pk = self.kwargs['pk'])
return context
class PublishersListView(ListView):
model = Publisher
context_object_name = 'publishers_list'
template_name = 'publishers_list.html'
paginate_by = 500
class PublisherBooksListView(ListView):
model = Book
context_object_name = 'publisher_books'
template_name = 'publisher_books.html'
paginate_by = 20
def get_queryset(self, **kwargs):
publisher_id = Publisher.objects.get(pk = self.kwargs['pk'])
qs = super().get_queryset(**kwargs)
return qs.filter(publisher = publisher_id)
def get_context_data(self, **kwargs):
# Call the base implementation first to get a context
context = super().get_context_data(**kwargs)
# Add in a QuerySet
context['publisher'] = Publisher.objects.get(pk = self.kwargs['pk'])
return context
class BooksListView(ListView):
model = Book
context_object_name = 'books_list'
template_name = 'books_list.html'
paginate_by = 100
class BookDetailView(DetailView):
model = Book
template_name = 'book_detail.html'
这是网址:
path('authors/', AuthorsListView.as_view(), name = 'authors_list'),
path('author/<int:pk>/', AuthorBooksListView.as_view(), name='author_detail'),
path('publishers/', PublishersListView.as_view(), name='publishers_list'),
path('publisher/<int:pk>/', PublisherBooksListView.as_view(), name='publisher_detail'),
path('', BooksListView.as_view(), name='books_list'),
path('book/<int:pk>/', BookDetailView.as_view(), name='book_detail'),
在我要显示的图书详情页面上:
- 同一作者的相关书籍
- 同一出版商的相关书籍
我怎样才能做到这一点?请帮助我。
我试图将这些代码添加到 BookDetailView:
def get_queryset(self, **kwargs):
book = Book.objects.get(pk = self.kwargs['pk'])
queryset = {
'books': Book.objects.all(),
'publisher_books': Book.objects.filter(publisher = book.publisher.id),
}
return queryset
但是它给我一个错误:
'dict' object has no attribute 'filter'
@djangodjarhes - 你能试试下面的方法吗?理想情况下,如果我想更改除 URL kwargs 之外的查询集过滤方式,我会修改 get_queryset。对于其他任何事情,我覆盖 get_context_data
def get_context_data(self, **kwargs):
context = super(BookDetailView, self).get_context_data(**kwargs)
book = Book.objects.get(pk = self.kwargs['pk'])
publisher_books = Book.objects.filter(publisher = book.publisher.id)
context["publisher_books"] = publisher_books
return context
关于你的情况,欢迎随时指正
queryset = {
'books': Book.objects.all(),
'publisher_books': Book.objects.filter(publisher = book.publisher.id),
}
这是不对的。当 get_queryset 应该 return 一个查询集时,你正在 returning 一个字典。你不能 return 听写。要么你改变它来做到这一点
queryset = Book.objects.filter(publisher = book.publisher.id)
return queryset
如果你想 return 字典,请使用 get_context_data。
我正在开发一个在线书店。 这是模型:
class Author(models.Model):
name = models.CharField(max_length=250, unique=True)
class Publisher(models.Model):
name = models.CharField(max_length=250, unique=True)
class Book(models.Model):
author = models.ManyToManyField(Author, related_name='authors')
publisher = models.ForeignKey(Publisher, on_delete=models.PROTECT, blank=True, null=True)
isbn13 = models.BigIntegerField(unique=True)
name = models.CharField(max_length=500)
...
视图如下:
class AuthorsListView(ListView):
model = Author
context_object_name = 'authors_list'
template_name = 'authors_list.html'
paginate_by = 500
class AuthorBooksListView(ListView):
model = Book
context_object_name = 'author_books'
template_name = 'author_books.html'
def get_queryset(self, **kwargs):
author_id = Author.objects.get(pk = self.kwargs['pk'])
qs = super().get_queryset(**kwargs)
return qs.filter(author = author_id)
def get_context_data(self, **kwargs):
# Call the base implementation first to get a context
context = super().get_context_data(**kwargs)
# Add in a QuerySet
context['author'] = Author.objects.get(pk = self.kwargs['pk'])
return context
class PublishersListView(ListView):
model = Publisher
context_object_name = 'publishers_list'
template_name = 'publishers_list.html'
paginate_by = 500
class PublisherBooksListView(ListView):
model = Book
context_object_name = 'publisher_books'
template_name = 'publisher_books.html'
paginate_by = 20
def get_queryset(self, **kwargs):
publisher_id = Publisher.objects.get(pk = self.kwargs['pk'])
qs = super().get_queryset(**kwargs)
return qs.filter(publisher = publisher_id)
def get_context_data(self, **kwargs):
# Call the base implementation first to get a context
context = super().get_context_data(**kwargs)
# Add in a QuerySet
context['publisher'] = Publisher.objects.get(pk = self.kwargs['pk'])
return context
class BooksListView(ListView):
model = Book
context_object_name = 'books_list'
template_name = 'books_list.html'
paginate_by = 100
class BookDetailView(DetailView):
model = Book
template_name = 'book_detail.html'
这是网址:
path('authors/', AuthorsListView.as_view(), name = 'authors_list'),
path('author/<int:pk>/', AuthorBooksListView.as_view(), name='author_detail'),
path('publishers/', PublishersListView.as_view(), name='publishers_list'),
path('publisher/<int:pk>/', PublisherBooksListView.as_view(), name='publisher_detail'),
path('', BooksListView.as_view(), name='books_list'),
path('book/<int:pk>/', BookDetailView.as_view(), name='book_detail'),
在我要显示的图书详情页面上:
- 同一作者的相关书籍
- 同一出版商的相关书籍 我怎样才能做到这一点?请帮助我。
我试图将这些代码添加到 BookDetailView:
def get_queryset(self, **kwargs):
book = Book.objects.get(pk = self.kwargs['pk'])
queryset = {
'books': Book.objects.all(),
'publisher_books': Book.objects.filter(publisher = book.publisher.id),
}
return queryset
但是它给我一个错误:
'dict' object has no attribute 'filter'
@djangodjarhes - 你能试试下面的方法吗?理想情况下,如果我想更改除 URL kwargs 之外的查询集过滤方式,我会修改 get_queryset。对于其他任何事情,我覆盖 get_context_data
def get_context_data(self, **kwargs):
context = super(BookDetailView, self).get_context_data(**kwargs)
book = Book.objects.get(pk = self.kwargs['pk'])
publisher_books = Book.objects.filter(publisher = book.publisher.id)
context["publisher_books"] = publisher_books
return context
关于你的情况,欢迎随时指正
queryset = {
'books': Book.objects.all(),
'publisher_books': Book.objects.filter(publisher = book.publisher.id),
}
这是不对的。当 get_queryset 应该 return 一个查询集时,你正在 returning 一个字典。你不能 return 听写。要么你改变它来做到这一点
queryset = Book.objects.filter(publisher = book.publisher.id)
return queryset
如果你想 return 字典,请使用 get_context_data。