PL/SQL 显示来自 Table 的具有条件的数据

Question

我正在尝试根据参与者的年龄显示姓名和类别

     CREATE OR REPLACE PROCEDURE categorie AS
     v_age NUMBER := 1;
     part_info participant%ROWTYPE;

     BEGIN 

     SELECT  *
     INTO part_info
     FROM Participant
     WHERE age > v_age;

     FOR i IN part_info
        IF(part_info.age<=18) THEN
             DBMS_OUTPUT.PUT_LINE('NAME: ' || part_info.nomParticipant  || 'CATEGORIE :  JUNIOR');
      
        ELSIF(part_info.age>=50) THEN
             DBMS_OUTPUT.PUT_LINE('NAME: ' || part_info.nomParticipant  || 'CATEGORIE :  SENIOR');

        ELSE 
             DBMS_OUTPUT.PUT_LINE('NAME: ' || part_info.nomParticipant  || 'CATEGORIE :  MIDDLE');
        END IF;
        END LOOP;
        END;

我错过了什么？

错误是“警告：创建的过程存在编译错误。”

Answer 1

首先，代码中缺少开头 LOOP，因此会引发错误。因此，您似乎想使用游标而不是单独使用 SELECT 语句，然后在 LOOP:

中将 part_info 限定符替换为 i

SQL> SET SERVEROUTPUT ON
SQL> CREATE OR REPLACE PROCEDURE categorie AS
     v_age  INT := 1;

     CURSOR part_info IS
     SELECT *      
       FROM Participant
      WHERE age > v_age;
BEGIN
   FOR i IN part_info
   LOOP     
        IF   i.age  <= 18  THEN
             DBMS_OUTPUT.PUT_LINE('NAME: ' || i.nomParticipant  || '  CATEGORIE :  JUNIOR');      
        ELSIF i.age >= 50 THEN
             DBMS_OUTPUT.PUT_LINE('NAME: ' || i.nomParticipant  || '  CATEGORIE :  SENIOR');
        ELSE
             DBMS_OUTPUT.PUT_LINE('NAME: ' || i.nomParticipant  || '  CATEGORIE :  MIDDLE');
        END IF;
   END LOOP;     
END;
/

PL/SQL 显示来自 Table 的具有条件的数据

PL/SQL Display Data From a Table with a Condition

oracle

plsql

database-cursor