你如何在 Oracle 中按此分组?

How do you group by this in Oracle?

SQL

SELECT DATE
     , SURFACE
     , SIZE1
     , SIZE2
     , SIZE3
     , SIZE4
     , QTY
FROM   TEST_TB
GROUP  BY SURFACE
     , SIZE1
     , SIZE2
     , SIZE3
     , SIZE4
ORDER  BY DATE
     , SURFACE
     , SIZE1
     , SIZE2
     , SIZE3
     , SIZE4

如何按 SURFACE、SIZE1、SIZE2、SIZE3、SIZE4 进行分组 并从 DATE 获取最早的日期并添加所有 QTY?
我想得到如下所示的结果,但无法正确...

SELECT MIN(date) AS date,
       surface,
       size1,
       size2,
       size3,
       size4,
       SUM(qty) AS qty
  FROM test_tb
  GROUP BY surface,
           size1,
           size2,
           size3,
           size4
  ORDER BY date,
           surface,
           size1,
           size2,
           size3,
           size4;

结果:

DATE     SURFACE    SIZE1      SIZE2      SIZE3      SIZE4             QTY
-------- ---------- ---------- ---------- ---------- ---------- ----------
01.02.21 2B         1.0        22.3       4000       0                   7
04.02.21 PL         5.3        10.0       3500       0                  10
07.02.21 PL         2.1        10.5       1800       0                   3
07.02.21 PL         4.8        8.0        600        0                   9

您对 2B 的期望值是错误的。最早的日期是 2021 年 2 月 1 日。