使用 pygame.draw.circle() 得到四分之一圆

Question

我和我的朋友正在尝试获得一个圆形精灵，我们用矩形做到了，但我们的代码显然得到了四分之一的圆。（顺便说一下，在我们的语言中，“sirkel”表示圆形，“firkant”表示矩形

我们不知道为什么会这样。这没有任何意义。我们试图改变位置，看看是否有重叠的东西，但没有。我们正在使用一个名为 Repl.it 的网站，因此可能存在一些问题，因为它非常有用，它会把东西弄乱，但不会那么多。

这是main.py:

import pygame
from firkant import Firkant
from sirkel import Sirkel
pygame.init()
PLAYER=0
screen = pygame.display.set_mode([600, 600])

from pygame.locals import (
  K_UP,
  K_DOWN,
  K_LEFT,
  K_RIGHT,
  K_ESCAPE,
  KEYDOWN,
  QUIT,
)

GREEN = (40,40,40)

pos1=60
pos2=235
pos3=410
posses = [pos1, pos2, pos3]

Firkant1 = Firkant(GREEN, 130, 130)
Firkant1.rect.x = pos1
Firkant1.rect.y = pos1
Firkant2 = Firkant(GREEN, 130, 130)
Firkant2.rect.x = pos2
Firkant2.rect.y = pos1
Firkant3 = Firkant(GREEN, 130, 130)
Firkant3.rect.x = pos3
Firkant3.rect.y = pos1
Firkant4 = Firkant(GREEN, 130, 130)
Firkant4.rect.x = pos1
Firkant4.rect.y = pos2
Firkant5 = Firkant(GREEN, 130, 130)
Firkant5.rect.x = pos2
Firkant5.rect.y = pos2
Firkant6 = Firkant(GREEN, 130, 130)
Firkant6.rect.x = pos3
Firkant6.rect.y = pos2
Firkant7 = Firkant(GREEN, 130, 130)
Firkant7.rect.x = pos1
Firkant7.rect.y = pos3
Firkant8 = Firkant(GREEN, 130, 130)
Firkant8.rect.x = pos2
Firkant8.rect.y = pos3
Firkant9 = Firkant(GREEN, 130, 130)
Firkant9.rect.x = pos3
Firkant9.rect.y = pos3
Sirkel1 = Sirkel((0,0,0), 400, 300)
all_sprites_list = pygame.sprite.Group()
all_sprites_list.add(Firkant1, Firkant2, Firkant3, Firkant4, Firkant5, Firkant6, Firkant7, Firkant8, Firkant9, Sirkel1)

for a in posses:
  x = a
  for b in posses:
    pass
running = True
while running:
  for event in pygame.event.get():
    if event.type == KEYDOWN:
      if event.key == K_ESCAPE:
        running = False
    screen.fill((100, 100, 100))
    all_sprites_list.update()
    all_sprites_list.draw(screen)

    pygame.display.flip()

pygame.quit()

这是square.py:

import pygame
WHITE = (255, 255, 255)
 
SS = 600
class Firkant(pygame.sprite.Sprite):
    
    def __init__(self, color, width, height):
        super().__init__()       
        self.image = pygame.Surface([width, height])
        self.image.fill(WHITE)
        self.image.set_colorkey(WHITE)
        pygame.draw.rect(self.image, color, (0, 0, width, height))        
        self.rect = self.image.get_rect()

这是circle.py

import pygame
WHITE = (255, 255, 255)
class Sirkel(pygame.sprite.Sprite):
    def __init__(self, color, width, height):
        super().__init__()
        self.image = pygame.Surface([width, height])
        self.image.fill(WHITE)
        self.image.set_colorkey(WHITE)
        pygame.draw.circle(self.image, color, (width, height), 200)
        self.rect = self.image.get_rect()

Answer 1

pygame.draw.circle的第3个参数为圆心。如果矩形是(width,height)大小，则中心点是(width // 2,height // 2):

~~pygame.draw.circle(self.image, color, (width, height), 200)~~

radius = min(width, height) // 2
pygame.draw.circle(self.image, color, (width // 2, height // 2), radius)

您还可以使用 pygame.Rect 对象的 center 属性：

self.rect = self.image.get_rect()
pygame.draw.circle(self.image, color, self.rect.center, min(self.rect.center))

使用 pygame.draw.circle() 得到四分之一圆

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