基于对象数组的 MongoDB 过滤器

MondoDB filter based on array of objects

我在集合中有这些类型的数据:

{
  "_id": {
    "$oid": "6014662b3a38ba4929b602ab"
  },
  "collection": [
    {
      "name": "Facility",
      "_id": {
        "$oid": "601466293a38ba4929b602aa"
      },
      "is_deleted": false
    },
    {
      "name": "User",
      "_id": {
        "$oid": "60021529c02fa2b27e7c1989"
      },
      "is_deleted": false
    },
    {
      "name": "Asset",
      "_id": {
        "$oid": "6018948fc35a109224439f73"
      },

    },
    {
      "name": "Asset",
      "_id": {
        "$oid": "604a734fca10c74d800031db"
      },
      "is_deleted": true
    }
  ],
  "customer": "TestCustomer",
  "is_deleted": false
}

我也有这个问题


db.getCollection("Collection").aggregate([{
    '$match': {
        '$and': [{
            'collection.name': 'User',
            'collection._id': ObjectId('60021529c02fa2b27e7c1989'),
            'collection.is_deleted': false
        }, {
            'collection.name': 'Asset',
            'collection._id': ObjectId('604a734fca10c74d800031db'),
            'collection.is_deleted': false
        }],
        'customer': 'TestCustomer',
        'is_deleted': false
    }
}])

is_deleted on Asset 在数据库中为真,但我在请求时值为 false

执行此查询时,不应该 return 没有数据,但确实如此。我一直在努力解决这个问题,但到目前为止没有任何帮助。

因为您要匹配数组中的元素,所以您应该改用 $elemMatch。也不需要 $and 运算符。

db.collection.aggregate([
  {
    "$match": {
      "collection": {
        "$elemMatch": {
          "name": "User",
          "_id": ObjectId("60021529c02fa2b27e7c1989"),
          "is_deleted": false
        }
      },
      "collection": {
        "$elemMatch": {
          "name": "Asset",
          "_id": ObjectId("604a734fca10c74d800031db"),
          "is_deleted": false
        }
      },
      "customer": "TestCustomer",
      "is_deleted": false
    }
  }
])

游乐场:https://mongoplayground.net/p/cdz9TgQ8HNw