将字符串转换为整数 JOptionPane
Converting String to Integer JOptionPane
我正在尝试从用户那里获取整数(年龄)的输入。但我不断收到“字符串无法转换为字符串”和“二元运算符 '<='and '>=' 的错误操作数类型。任何帮助将不胜感激
import javax.swing.JOptionPane;
class LotionFinder {
public static void main(String[] args) {
String response;
response = Integer.parseInt(JOptionPane.showInputDialog ("Please Enter Your Age:"));
if (response == null) {
JOptionPane.showMessageDialog(null, "Please Contact a Sales Representative For a Private Consultation");
} else if (response.equals("")) {
JOptionPane.showMessageDialog(null, "Please Contact a Sales Representative For a Private Consultation");
} else if (response <= 3 && response >= 1){
JOptionPane.showMessageDialog(null, "It's Recommended That You Purchase Our No-Tears Baby Lotion!");
}
System.exit (0);
}
}
我建议首先从 JOptionPane 获取值作为 String
String response = JOptionPane.showInputDialog ("Please Enter Your Age:");
然后检查用户是否输入了内容然后将其解析为Integer
if (response.length() !=0) {
responseToInt = Integer.parseInt(response);
通过 try and catch,我们可以限制用户只能输入数字。
try {
responseToInt = Integer.parseInt(response);
}catch (NumberFormatException e){
System.out.println("Please enter a number");
response = JOptionPane.showInputDialog ("Please Enter Your Age:");
}
完整代码
public static void main(String[] args) {
Integer responseToInt = 0;
String response = JOptionPane.showInputDialog ("Please Enter Your Age:");
if (response.length() !=0) {
try {
responseToInt = Integer.parseInt(response);
}catch (NumberFormatException e){
System.out.println("Please enter a number");
response = JOptionPane.showInputDialog ("Please Enter Your Age:");
}
} if (responseToInt <= 3 && responseToInt >= 1){
JOptionPane.showMessageDialog(null, "It's Recommended That You Purchase Our No-Tears Baby Lotion!");
}else{
JOptionPane.showMessageDialog(null, "Please Contact a Sales Representative For a Private Consultation");
}
}
}
我正在尝试从用户那里获取整数(年龄)的输入。但我不断收到“字符串无法转换为字符串”和“二元运算符 '<='and '>=' 的错误操作数类型。任何帮助将不胜感激
import javax.swing.JOptionPane;
class LotionFinder {
public static void main(String[] args) {
String response;
response = Integer.parseInt(JOptionPane.showInputDialog ("Please Enter Your Age:"));
if (response == null) {
JOptionPane.showMessageDialog(null, "Please Contact a Sales Representative For a Private Consultation");
} else if (response.equals("")) {
JOptionPane.showMessageDialog(null, "Please Contact a Sales Representative For a Private Consultation");
} else if (response <= 3 && response >= 1){
JOptionPane.showMessageDialog(null, "It's Recommended That You Purchase Our No-Tears Baby Lotion!");
}
System.exit (0);
}
}
我建议首先从 JOptionPane 获取值作为 String
String response = JOptionPane.showInputDialog ("Please Enter Your Age:");
然后检查用户是否输入了内容然后将其解析为Integer
if (response.length() !=0) {
responseToInt = Integer.parseInt(response);
通过 try and catch,我们可以限制用户只能输入数字。
try {
responseToInt = Integer.parseInt(response);
}catch (NumberFormatException e){
System.out.println("Please enter a number");
response = JOptionPane.showInputDialog ("Please Enter Your Age:");
}
完整代码
public static void main(String[] args) {
Integer responseToInt = 0;
String response = JOptionPane.showInputDialog ("Please Enter Your Age:");
if (response.length() !=0) {
try {
responseToInt = Integer.parseInt(response);
}catch (NumberFormatException e){
System.out.println("Please enter a number");
response = JOptionPane.showInputDialog ("Please Enter Your Age:");
}
} if (responseToInt <= 3 && responseToInt >= 1){
JOptionPane.showMessageDialog(null, "It's Recommended That You Purchase Our No-Tears Baby Lotion!");
}else{
JOptionPane.showMessageDialog(null, "Please Contact a Sales Representative For a Private Consultation");
}
}
}