C# 覆盖默认接口方法

Question

是否可以在另一个接口中覆盖默认接口方法？

假设我有以下代码：

public class Program
{
    public static void Main()
    {
        IOriginal origOrig = new Original();
        IOriginal origInh = new Inherited();
        IInherited inherited = new Inherited();
        
        Console.WriteLine($"IOriginal Original: {origOrig.Method()}");
        Console.WriteLine($"IOriginal Inherited: {origInh.Method()}");
        Console.WriteLine($"IInherited Inherited: {inherited.Method()}");
    }
}

public interface IOriginal
{
    string Method() => "original";
}

public interface IInherited : IOriginal
{
    string Method() => "inherited";
}

public class Inherited : IInherited {}
public class Original : IOriginal {}

输出为

IOriginal Original: original
IOriginal Inherited: original
IInherited Inherited: inherited

但是，我想重写 IInherited 接口中的方法，所以它产生了这个：

IOriginal Original: original
IOriginal Inherited: inherited
IInherited Inherited: inherited

在C# 8 specification proposal中，有人提出这样做：

interface IA
{
    void M() { WriteLine("IA.M"); }
}
interface IB : IA
{
    override void IA.M() { WriteLine("IB.M"); } // explicitly named
}
interface IC : IA
{
    override void M() { WriteLine("IC.M"); } // implicitly named
}

但在正式版中，它不起作用？

Compilation error: The modifier 'override' is not valid for this item

有什么办法可以实现吗？

Answer 1

使用：

interface IB : IA
{
    void IA.M() { WriteLine("IB.M"); } // explicitly named
}

appears to work.

我找不到任何 C# 文档说这是正确的语法！

C# 覆盖默认接口方法

C# Overriding default interface methods

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