在 golang 中，[:] 语法与数组赋值有何不同？

Question

我目前正在阅读 GoLang 教程并有以下疑问。

arr1:=[...]int{1,2,3}
arr2:=arr1
arr1[1]=99
fmt.Println(arr1)
fmt.Println(arr2)

它输出以下语句

[1 99 3]
[1 2 3]

here only array a is modified, which makes sense as an array is treated as values.

如果我尝试跟随事情会变得混乱

a:=[...]int{1,2,3}
b:=a[:]
a[1]=88
fmt.Println(a)
fmt.Println(b)

这导致打印

[1 88 3]
[1 88 3]

问题：这是否意味着说 b:=a 会创建数组的副本，而说 b:=a[:] 会创建一个指向底层数组的切片（在本例中为 'a'）？

Answer 1

Slicing does not copy the slice's data. It creates a new slice value that points to the original array. This makes slice operations as efficient as manipulating array indices. Therefore, modifying the elements (not the slice itself) of a re-slice modifies the elements of the original slice

https://blog.golang.org/slices-intro

检查上面 link 以了解 Slice 背后的内部结构

在 golang 中，[:] 语法与数组赋值有何不同？

in golang what does the [:] syntax differ from the array assignment?

arrays

go

slice