识别错误属于可观察列表的哪个可观察对象

Question

const obs1$ = this.service.getAllSources();
const obs2$ = this.service.getWidgetById(1);

combineLatest([obs1$, obs2$])
   .subscribe(pair => {
      const sources = pair[0];
      const widget = pair[1];
      // do stuff
   }, err => {
       // err can be from first or second observable, but which?    
       if (err.status === 404) {
          // here I need to know for which observable the error is ocurred ?!?!
          this.utilsService.alert('Widget with id 1 not found');
       }
       
       if (err.status === 500) {
          // here, I need to know from which observable occured
       }
   });

从后端我从来没有发送 404 status 来获取列表，因此，在这种情况下，我可以确定 404 仅来自第二个可观察对象。但是如果我想在 error 方法中有另一个逻辑，我需要知道它是从哪个 observable 发生的。我该怎么做？谢谢

Answer 1

您可以将每个 observable 包装在 catchError 中并分别处理它们：

combineLatest([
obs1$.pipe(catchError(e => ...)), 
obs2$.pipe(catchError(e => ...)),
]).subscribe(...)

或者您可以标记错误并在 subscribe 中处理它们。好像

obs1$.pipe(catchError(e => throwError({originalError: e, source: 'whatever you want'}))),

识别错误属于可观察列表的哪个可观察对象

Identify of which observable the error belongs for a list of observables

error-handling

observable

rxjs

typescript

angular