jquery 未填充 select
jquery not populating select
我正在使用 jquery 和 jquery 移动设备来简单地填充 select 元素。这是 js:
var SelectDropDown = $("#searchuniversity");
SelectDropDown.empty();
var NewOption = new Option("Select University" ,"");
SelectDropDown.add(NewOption);
for (var i = 0; i < ArrayUniversisities.length ; i++)
{
var NewOption = new Option(ArrayUniversisities[i] ,i);
SelectDropDown.add(NewOption);
SelectDropDown.selectedIndex = 0;
};
这是 HTML:
<select name="searchuniversity" id="searchuniversity" required></select>
为什么这不起作用?
使用 append 而不是添加:
var SelectDropDown = $("#searchuniversity");
SelectDropDown.empty();
var NewOption = new Option("Select University" ,"");
var ArrayUniversisities = [1, 2, 3, 4];
SelectDropDown.append(NewOption);
for (var i = 0; i < ArrayUniversisities.length ; i++)
{
var NewOption = new Option(ArrayUniversisities[i] ,i);
SelectDropDown.append(NewOption);
SelectDropDown.selectedIndex = 0;
};
使用'append'代替'add'
var ArrayUniversisities = [ 15, 16, 17 ]; // I don't know what you had in your original array, but here's a simple example.
var SelectDropDown = $("#searchuniversity");
SelectDropDown.empty();
var NewOption = new Option("Select University" ,"");
SelectDropDown.append(NewOption); // Use append instead of add.
for (var i = 0; i < ArrayUniversisities.length ; i++)
{
var NewOption = new Option(ArrayUniversisities[i] ,i);
SelectDropDown.append(NewOption); // Use append instead of add.
SelectDropDown.selectedIndex = 0;
};
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<select name="searchuniversity" id="searchuniversity" required></select>
Add (http://api.jquery.com/add/) 在 selection 类型的环境中使用,例如,如果您正在查找多个元素,并想向该查找添加另一个项目。
Append (http://api.jquery.com/append/) 会将选项元素附加到 select 元素。
我正在使用 jquery 和 jquery 移动设备来简单地填充 select 元素。这是 js:
var SelectDropDown = $("#searchuniversity");
SelectDropDown.empty();
var NewOption = new Option("Select University" ,"");
SelectDropDown.add(NewOption);
for (var i = 0; i < ArrayUniversisities.length ; i++)
{
var NewOption = new Option(ArrayUniversisities[i] ,i);
SelectDropDown.add(NewOption);
SelectDropDown.selectedIndex = 0;
};
这是 HTML:
<select name="searchuniversity" id="searchuniversity" required></select>
为什么这不起作用?
使用 append 而不是添加:
var SelectDropDown = $("#searchuniversity");
SelectDropDown.empty();
var NewOption = new Option("Select University" ,"");
var ArrayUniversisities = [1, 2, 3, 4];
SelectDropDown.append(NewOption);
for (var i = 0; i < ArrayUniversisities.length ; i++)
{
var NewOption = new Option(ArrayUniversisities[i] ,i);
SelectDropDown.append(NewOption);
SelectDropDown.selectedIndex = 0;
};
使用'append'代替'add'
var ArrayUniversisities = [ 15, 16, 17 ]; // I don't know what you had in your original array, but here's a simple example.
var SelectDropDown = $("#searchuniversity");
SelectDropDown.empty();
var NewOption = new Option("Select University" ,"");
SelectDropDown.append(NewOption); // Use append instead of add.
for (var i = 0; i < ArrayUniversisities.length ; i++)
{
var NewOption = new Option(ArrayUniversisities[i] ,i);
SelectDropDown.append(NewOption); // Use append instead of add.
SelectDropDown.selectedIndex = 0;
};
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<select name="searchuniversity" id="searchuniversity" required></select>
Add (http://api.jquery.com/add/) 在 selection 类型的环境中使用,例如,如果您正在查找多个元素,并想向该查找添加另一个项目。
Append (http://api.jquery.com/append/) 会将选项元素附加到 select 元素。