逐行读取文件并使用 split() 函数使用 python 将行分成整数列表

Question

我已经逐行阅读了文件，但现在不知道如何将这些行变成整数列表。

这是我的：

def adjMatrixFromFile(文件):

Our_numbers = []
file = open(file, 'r')
n =0
while True: 
    line = file.readlines()
    if not line:
        break
    for i in line: 
        numbers = i.split(' ')
        Our_numbers.append(numbers) 
new_ourNumbers = []
for d in Our_numbers:
    for k in d:
        result = k.split(' ')
        new_ourNumbers.append(result)    
return new_ourNumbers

打印（adjMatrixFromFile（“文件”））

这是文件：

''''5 
    0 1 
    1 2  1 2  1 3  1 3  1 4 
    2 3 
    3 0 
    4 0  4 2

Answer 1

用这个“tiny.txt”：

5 
0 1 
1 2  1 2  1 3  1 3  1 4 
2 3 
3 0 
4 0  4 2

和这段代码：

def adjMatrixFromFile(file):
    Our_numbers = []
    file = open(file, 'r')
    line = file.readlines()

    for i in line:
        i=i.replace('\n','') #remove all \n 
        numbers = i.split(' ')
        numbers = filter(None, numbers) #remove '' in the list
        Our_numbers.extend(numbers) #add values from a list to another list

    Our_numbers = [int(i) for i in Our_numbers] #convert all element str -> int
    return Our_numbers

print(adjMatrixFromFile("tiny.txt"))

我得到了这个输出：

[5, 0, 1, 1, 2, 1, 2, 1, 3, 1, 3, 1, 4, 2, 3, 3, 0, 4, 0, 4, 2]

Answer 2

假设文件看起来像这样：

1 5 13
-7 8 99
10 0 1

使其成为一个简单的整数列表：

our_numbers = []
for line in open(filename):
    our_numbers.extend( [ int(num) for num in line.split() ] )

如果行中的某个元素无法解析为整数，您将收到 ValueError。

使其成为类似于“列表列表”的矩阵：

our_numbers = []
for line in open(filename):
    our_numbers.append( [ int(num) for num in line.split() ] )

逐行读取文件并使用 split() 函数使用 python 将行分成整数列表

Read the file line-by-line and use the split() function to break the line into a list of integers using python

python

integer

split

list