未定义的偏移量：1 laravel

Question

我是 laravel 的新手我有一个带有动态字段的表单，但是当我创建多个动态字段并单击“提交”时，会出现此错误：Undefined offset: 1 但它只适用于一个领域。我看到谁用过 isset 但我不知道如何在我的案例中使用它谁能告诉我为什么 php

会出现这样的错误

控制器：

   public function store(Request $request)

{   
    
    $data['invoice_no'] = $request->invoice_no;
        
    $data['last_invoice_no'] = $request->last_invoice_no;
    $data['devise'] = $request->devise;
    $data['customer_name'] = $request->customer_name;
    $data['customer_adress'] = $request->customer_adress;
    $data['invoice_no'] = $request->invoice_no;
    $data['invoice_date'] = $request->invoice_date;
  
    $data['company_adress'] = $request->company_adress;
    $data['company_name'] = $request->company_name;
    $data['company_phone'] = $request->company_phone;
    $data['poids_brut'] = $request->poids_brut;
    $data['poids_net'] = $request->poids_net;
    $data['livraison'] = $request->livraison;
    $data['incoterm'] = $request->incoterm;
    $data['payment_details'] = $request->payment_details;
    $data['sub_total'] = $request->sub_total;
    $data['shipping'] = $request->shipping;
    $data['total_due'] = $request->total_due;
    $data['created_by'] = (Auth::user()->name);

    $invoices = Invoices::create($data);

    $details_list = [];
    for ($i = 0; $i < count($request->categorie_id); $i++) {
       
                              
        $details_list[$i]['categorie_id'] = $request->categorie_id[$i];
        $details_list[$i]['product_id'] = $request->product_id[$i];
        $details_list[$i]['size_id'] = $request->size_id[$i];
        $details_list[$i]['quantity'] = $request->quantity[$i];
        $details_list[$i]['unit_price'] = $request->unit_price[$i];
        $details_list[$i]['total_price'] = $request->total_price[$i];
        $details_list[$i]['created_by'] = (Auth::user()->name);
   
               }

    $details = $invoices->details()->createMany($details_list);

    if ($details) {
        return redirect('/invoices')->with([
            'message' => __('la facture est créé avec succès'),
            'alert-type' => 'success'
        ]);
    } else {
        return redirect()->back()->with([
            'message' => __('la creation de facture a échoué'),
            'alert-type' => 'danger'
        ]);
    }
   

   }

发票模型：

class invoices extends Model
{
     protected $guarded=[];
    public function details()
    {
        return $this->hasMany(invoice_products::class, 'invoice_id', 'id');
    }
}

发票产品型号：

class invoice_products extends Model
{
    protected $guarded=[];

    public function invoice()
    {
        return $this->belongsTo(Invoices::class, 'invoice_id', 'id');
    }
}

Answer 1

原因：

this error appears: Undefined offset: 1

你可以找到解释Here

您的案例：

for ($i = 0; $i < count($request->categorie_id); $i++) { $details_list[$i]['categorie_id'] = $request->categorie_id[$i];

也许（因为我们不知道您从 form 传递的是什么）您的 $request->categorie_id 没有 key/index 1。因此，在您的 for 循环中，它寻找 $request->categorie_id[1] 并失败抛出错误 Undefined offset: 1，这意味着数组 $request->categorie_id[] 没有 key/index/offset 1.

建议：

您可以 dd($request->all()); 或 dd($request->categorie_id); 在您的存储方法中查看里面的内容以确保它包含 $request->categorie_id[] 索引为 1

的数组

未定义的偏移量：1 laravel

Undefined offset: 1 laravel

controller

model

store

laravel

原因：

您的案例：

建议：