Python Selenium find_element_by_id 如果找不到则默认

Question

我想通过id在页面上找到一个元素。问题是这个元素只是暂时的，不会一直存在。因此我想设置默认值，这样我就可以像这样在条件下检查它：

    covidPopUp = driver.find_element_by_id("sgpb-popup-dialog-main- 
    div").extract(default='not-found')

    if(covidPopUp == 'not-found'):
        load_more_btn = driver.find_element_by_id("load_more_button")
        load_more_btn.click()
    else:
        popUpClose = driver.find_element_by_id("sgpb-popup-close-button-6")
        popUpClose.click()

但是，这会产生以下错误：

AttributeError: 'WebElement' object has no attribute 'extract'

Answer 1

我想你有几个选择。

使用find_element_by_id但捕获异常

from selenium.common.exceptions import NoSuchElementException
try:
    covidPopUp = driver.find_element_by_id("sgpb-popup-dialog-main-div")
except NoSuchElementException:
    covidPopUp = "not-found"

使用find_elements_by_id（注意复数）并检查列表是否为空。

covidPopUp = driver.find_elements_by_id("sgpb-popup-dialog-main-div")
covidPopUp = covidPopUp[0] if covidPopUp else "not-found"

Python Selenium find_element_by_id 如果找不到则默认

Python Selenium find_element_by_id with default if not found

python

selenium

scrapy

web-scraping

selenium-webdriver