Python 字符串比较

Question

我想使用 wp_scan 扫描我的 wordpress 网站以寻找新插件。我想要一个 python 每天显示给我的脚本

易受攻击的插件列表
新插件列表。

编写一个只给我输出的易受攻击插件的解析器并不复杂。但是我如何编写解析器（或以何种方式）以便我只获得一个新插件列表。

示例 -（示例来源 - 我对其进行了一些修改 http://www.blackmoreops.com/2013/10/14/wpscan-and-quick-wordpress-security/）。第一天：

___________________________________________________
__          _______   _____
\ \        / /  __ \ / ____|
\ \  /\  / /| |__) | (___   ___  __ _ _ __
\ \/  \/ / |  ___/ \___ \ / __|/ _` | '_ \
\  /\  /  | |     ____) | (__| (_| | | | |
\/  \/   |_|    |_____/ \___|\__,_|_| |_| v2.1rNA
WordPress Security Scanner by the WPScan Team
Sponsored by the RandomStorm Open Source Initiative
_____________________________________________________
| URL: http://www.blackmoreops.com/
| Started on Sun Oct 13 13:39:25 2013
[31m[!][0m The WordPress 'http://www.blackmoreops.com/readme.html' file exists
[31m[!][0m Full Path Disclosure (FPD) in 'http://www.blackmoreops.com/wp-includes/rss-functions.php'
[32m[+][0m XML-RPC Interface available under http://www.blackmoreops.com/xmlrpc.php
[32m[+][0m WordPress version 3.6.1 identified from meta generator
[32m[+][0m The WordPress theme in use is twentyten v1.6
| Name: twentyten v1.6
| Location: http://www.blackmoreops.com/wp-content/themes/twentyten/
[32m[+][0m Enumerating plugins from passive detection ...
2 plugins found :
| Name: add-to-any v1.2.5
| Location: http://www.blackmoreops.com/wp-content/plugins/add-to-any/
| Directory listing enabled: Yes
| Readme: http://www.blackmoreops.com/wp-content/plugins/add-to-any/README.txt
| Name: captcha v3.8.4
| Location: http://www.blackmoreops.com/wp-content/plugins/captcha/
| Directory listing enabled: Yes
| Readme: http://www.blackmoreops.com/wp-content/plugins/captcha/readme.txt
[32m[+] Finished at Sun Oct 13 13:39:51 2013[0m
[32m[+] Elapsed time: 00:00:26[0m]

次日：

___________________________________________________
__          _______   _____
\ \        / /  __ \ / ____|
\ \  /\  / /| |__) | (___   ___  __ _ _ __
\ \/  \/ / |  ___/ \___ \ / __|/ _` | '_ \
\  /\  /  | |     ____) | (__| (_| | | | |
\/  \/   |_|    |_____/ \___|\__,_|_| |_| v2.1rNA
WordPress Security Scanner by the WPScan Team
Sponsored by the RandomStorm Open Source Initiative
_____________________________________________________
| URL: http://www.blackmoreops.com/
| Started on Sun Oct 13 13:39:25 2013
[31m[!][0m The WordPress 'http://www.blackmoreops.com/readme.html' file exists
[31m[!][0m Full Path Disclosure (FPD) in 'http://www.blackmoreops.com/wp-includes/rss-functions.php'
[32m[+][0m XML-RPC Interface available under http://www.blackmoreops.com/xmlrpc.php
[32m[+][0m WordPress version 3.6.1 identified from meta generator
[32m[+][0m The WordPress theme in use is twentyten v1.6
| Name: twentyten v1.6
| Location: http://www.blackmoreops.com/wp-content/themes/twentyten/
[32m[+][0m Enumerating plugins from passive detection ...
3 plugins found :
| Name: add-to-any v1.2.5
| Location: http://www.blackmoreops.com/wp-content/plugins/add-to-any/
| Directory listing enabled: Yes
| Readme: http://www.blackmoreops.com/wp-content/plugins/add-to-any/README.txt
| Name: captcha v3.8.4
| Location: http://www.blackmoreops.com/wp-content/plugins/captcha/
| Directory listing enabled: Yes
| Readme: http://www.blackmoreops.com/wp-content/plugins/captcha/readme.txt
| Name: google-analyticator v6.4.5
| Location: http://www.blackmoreops.com/wp-content/plugins/google-analyticator/
| Directory listing enabled: Yes
| Readme: http://www.blackmoreops.com/wp-content/plugins/google-analyticator/readme.txt
[32m[+] Finished at Sun Oct 14 13:39:51 2013[0m
[32m[+] Elapsed time: 00:00:26[0m]

我是否应该始终在 [+] 之后分隔字符串并比较它们（我不知道输出列表是如何排序的——我认为是字母顺序的——所以我不能只得到最后的插件并说这是我的新插件）？那有效率吗？让问题简单化：

第一个字符串：

Hallo
Pet
Me

第二个字符串：

Hallo
World
Pet
Me

如何高效地找出新词？

Answer 1

解决您的简化示例：

str1 = "Hallo Pet Me"
str2 = "Hallo World Pet Me"

set1 = set(str1.split())
set2 = set(str2.split())
print set2 - set1

你有两组字符串，你想获取第二组字符串而不是第一组字符串。

Answer 2

首先将字符串拆分为列表，然后打印第二个字符串中的每个单词，因为它不是第一个字符串。

    str1 = "Hallo Pet Me"
    str2 = "Hallo World Pet Me"
    split1 = str1.split()
    split2 = str2.split()
    print [word for word in split2 if word not in split1]

如果您想忽略 lower/uppercase 中的差异：

    str1 = "Hallo Pet Me"
    str2 = "Hallo World Pet Me"
    split1 = str1.lower().split()
    split2 = str2.lower().split()
    print [word for word in split2 if word not in split1]

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