如何通过networkx绘制每个节点?
how to draw each node by networkx?
我知道有个函数,nx.draw_networkx_nodes(G, pos, node_size=200, node_color='#00b4d9')
可以画出网络中的所有节点。但是,我的每个节点都有不同的颜色、数据集和代码,
df_name = ['A','B','C','D','E']
val_idx = [1,2,3,4,5]
pred_pca_spec = [1,2,0,1,4]
#Note! below is rgb color value of each sample
val_rgb = [[130, 89, 34],[170, 133, 75],[126, 85, 17],[120, 81, 37],[162, 126, 65]]
G = nx.Graph()
G.add_node('no.1')
pos = nx.spring_layout(G)
for i in range(0, len(df_name)):
if pred_pca_spec[i] == 1:
G.add_edge('no.1', int(val_idx[i])) # I want to set color in this line at same time,like
######G.add_edge('no.1', node_value = int(val_idx[i]), node_color = '#%02x%02x%02x' % tuple(val_rgb[i]))#####
nx.draw_networkx(G)
plt.show()
有什么功能可以实现吗?
注意!因为数据集是染料纺织品样本所以我必须显示它们的真实颜色,只能使用rgb颜色space,不能
colors = ["r", "g", "b", "y", "w"]
拜托!
我仍然不确定,你的问题到底是什么,你在哪里遇到困难,或者你为什么要在 for 循环中添加颜色。
但是,我希望以下代码可以解决您的问题。
使用 我将你的 RGB 转换为 0 到 1 之间的值。
import networkx as nx
import matplotlib.pylab as plt
df_name = ["A", "B", "C", "D", "E"]
val_idx = [1, 2, 3, 4, 5]
pred_pca_spec = [1, 2, 0, 1, 4]
val_rgb = [[130, 89, 34],
[170, 133, 75],
[126, 85, 17],
[120, 81, 37],
[162, 126, 65], ]
val_rgb = [(r / 255, g / 255, b / 255) for r, g, b in val_rgb]
G = nx.Graph()
G.add_node('no.1')
G.nodes['no.1']["color"] = tuple(val_rgb[0]) # or whatever color you like
pos = nx.spring_layout(G)
for i in range(0, len(df_name)):
if pred_pca_spec[i] == 1:
node = int(val_idx[i])
G.add_edge('no.1', node)
G.nodes[node]["color"] = val_rgb[i]
nx.draw_networkx(G, node_color=[G.nodes[node]["color"] for node in G])
plt.show()
结果
我知道有个函数,nx.draw_networkx_nodes(G, pos, node_size=200, node_color='#00b4d9')
可以画出网络中的所有节点。但是,我的每个节点都有不同的颜色、数据集和代码,
df_name = ['A','B','C','D','E']
val_idx = [1,2,3,4,5]
pred_pca_spec = [1,2,0,1,4]
#Note! below is rgb color value of each sample
val_rgb = [[130, 89, 34],[170, 133, 75],[126, 85, 17],[120, 81, 37],[162, 126, 65]]
G = nx.Graph()
G.add_node('no.1')
pos = nx.spring_layout(G)
for i in range(0, len(df_name)):
if pred_pca_spec[i] == 1:
G.add_edge('no.1', int(val_idx[i])) # I want to set color in this line at same time,like
######G.add_edge('no.1', node_value = int(val_idx[i]), node_color = '#%02x%02x%02x' % tuple(val_rgb[i]))#####
nx.draw_networkx(G)
plt.show()
有什么功能可以实现吗? 注意!因为数据集是染料纺织品样本所以我必须显示它们的真实颜色,只能使用rgb颜色space,不能
colors = ["r", "g", "b", "y", "w"]
拜托!
我仍然不确定,你的问题到底是什么,你在哪里遇到困难,或者你为什么要在 for 循环中添加颜色。
但是,我希望以下代码可以解决您的问题。
使用
import networkx as nx
import matplotlib.pylab as plt
df_name = ["A", "B", "C", "D", "E"]
val_idx = [1, 2, 3, 4, 5]
pred_pca_spec = [1, 2, 0, 1, 4]
val_rgb = [[130, 89, 34],
[170, 133, 75],
[126, 85, 17],
[120, 81, 37],
[162, 126, 65], ]
val_rgb = [(r / 255, g / 255, b / 255) for r, g, b in val_rgb]
G = nx.Graph()
G.add_node('no.1')
G.nodes['no.1']["color"] = tuple(val_rgb[0]) # or whatever color you like
pos = nx.spring_layout(G)
for i in range(0, len(df_name)):
if pred_pca_spec[i] == 1:
node = int(val_idx[i])
G.add_edge('no.1', node)
G.nodes[node]["color"] = val_rgb[i]
nx.draw_networkx(G, node_color=[G.nodes[node]["color"] for node in G])
plt.show()
结果