Tkinter：检索单选按钮列和行值

Question

在这里我找到了一个很好的代码，我想修改并使用它。

原文如下：

from tkinter import *

root = Tk()

def showGrid():
    row    = btn.grid_info()['row']      # Row of the button
    column = btn.grid_info()['column']   # grid_info will return dictionary with all grid elements (row, column, ipadx, ipday, sticky, rowspan and columnspan)
    print("Grid position of 'btn': {} {}".format(row, column))

btn = Button(root, text = 'Click me!', command = showGrid)
btn.grid(row = 0, column = 0)

root.mainloop()

如果按钮是 2 个，def 将如何识别我点击了哪个按钮？我试图将按钮更改为单选按钮（这对我来说很好），设置一个值，设置一个变量，ecc，尝试使用 .get() 等等，但我无法清楚地识别单个单选按钮.

有什么建议吗？

最佳

Answer 1

使用 lambda 可能会有帮助。

from tkinter import *

root = Tk()

def showGrid(widget):
    row    = widget.grid_info()['row']      # Row of the button
    column = widget.grid_info()['column']   # grid_info will return dictionary with all grid elements (row, column, ipadx, ipday, sticky, rowspan and columnspan)
    print("Grid position of 'btn': {} {}".format(row, column))

btn = Button(root, text = 'Click me!', command = lambda: showGrid(btn))
btn.grid(row = 0, column = 0)
btn1 = Button(root, text = 'Click me!', command = lambda: showGrid(btn1))
btn1.grid(row = 1, column = 0)


root.mainloop()

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