给定 Colab 中的文件夹路径，我如何在 python 中提取其中的特定部分？
Given a folder path in Colab, how can I extract a specific portion of that in python?
例如，我的文件夹路径为 "/content/data/a/b/c/d/"
如何从此路径中提取“b”？
如果“b”永远不会移动
file_path = "/content/data/a/b/c/d/"
file_path.split('/')[4]
如果它移动了
file_path = "/content/data/a/b/c/d/"
file_path[file_path.index("b")]
>>> from pathlib import Path
>>> file_path = "/content/data/a/b/c/d/"
>>> p = Path(file_path).parts
>>> p
('\', 'content', 'data', 'a', 'b', 'c', 'd')
>>> b = p[4]
>>> b
'b'
例如，我的文件夹路径为 "/content/data/a/b/c/d/" 如何从此路径中提取“b”？
如果“b”永远不会移动
file_path = "/content/data/a/b/c/d/"
file_path.split('/')[4]
如果它移动了
file_path = "/content/data/a/b/c/d/"
file_path[file_path.index("b")]
>>> from pathlib import Path
>>> file_path = "/content/data/a/b/c/d/"
>>> p = Path(file_path).parts
>>> p
('\', 'content', 'data', 'a', 'b', 'c', 'd')
>>> b = p[4]
>>> b
'b'