检查输入任务的时间是否已过

Question

我正在尝试制作一个待办事项列表，您可以在其中通过 TKinter 输入格式为 'take out dog at 13:45' 的任务。然后我将任务中提到的时间作为日期时间对象处理，我将其与当前时间进行比较以查看任务是否到期。但是，我运行对它的结构遇到了一些麻烦。

我想让 sound_alarm 函数连续地运行，以检查任务是否到期。但我不能用 while true: loop 来做到这一点，因为它会干扰 TKinter 的 root.mainloop()。

知道如何让它在您输入任务时，sound_alarm 函数从该点开始运行ning 以检查是否有任何任务到期了吗？

这是我现在的代码：

import tkinter as tk
from tkinter import messagebox
import pickle
from datetime import datetime

root = tk.Tk()
root.title("To Do list")


def add_task():
    task = entry_task.get()
    if task != "":
        listbox_task.insert(tk.END, task)
        print(task)
        entry_task.delete(0, tk.END)
    else:
        tk.messagebox.showwarning(title="Warning", message="Enter a task first")


def del_task():
    try:
        task_index = listbox_task.curselection()[0]
        listbox_task.delete(task_index)
    except:
        tk.messagebox.showwarning(title="Warning", message="Select a task first")


def load_tasks():
    try:
        tasks = pickle.load(open("tasks.dat", "rb"))
        listbox_task.delete(0, tk.END)
        for task in tasks:
            listbox_task.insert(tk.END, task)
    except:
        tk.messagebox.showwarning(title="Warning", message="Cannot find task file")


def save_tasks():
    tasks = listbox_task.get(0, listbox_task.size())
    pickle.dump(tasks, open("tasks.dat", "wb"))


def get_time_from_task(task):
    time = task.split("at ", 1)[1]
    datetime_time = datetime.strptime(time, '%H:%M').time()
    return datetime_time


def sound_alarm():
    tasks = listbox_task.get(0, listbox_task.size())
    now = datetime.now().time()

    for task in tasks:
        datetime_time = get_time_from_task(task)
        print(datetime_time, now)
        if now > datetime_time:
            print(task, "is due!")


frame_tasks = tk.Frame(root)
frame_tasks.pack()

listbox_task = tk.Listbox(frame_tasks, height=20, width=50)
listbox_task.pack(side=tk.LEFT)

scrollbar_tasks = tk.Scrollbar(frame_tasks)
scrollbar_tasks.pack(side=tk.RIGHT, fill=tk.Y)

listbox_task.config(yscrollcommand=scrollbar_tasks.set)
scrollbar_tasks.config(command=listbox_task.yview)

entry_task = tk.Entry(root, width=50)
entry_task.pack()

btn_add = tk.Button(root, text="Add task", width=48, command=add_task)
btn_add.pack()

btn_del = tk.Button(root, text="Delete task", width=48, command=del_task)
btn_del.pack()

btn_load = tk.Button(root, text="Load tasks", width=48, command=load_tasks)
btn_load.pack()

btn_save = tk.Button(root, text="Save tasks", width=48, command=save_tasks)
btn_save.pack()

root.mainloop()

Answer 1

您可以使用.after()每分钟执行sound_alarm()。

以下修改sound_alarm():

def sound_alarm():
    tasks = listbox_task.get(0, "end")
    now = datetime.now()
    current_time = now.time()
    for task in tasks:
        task_time = get_time_from_task(task)
        print(task_time, current_time)
        if current_time > task_time:
            print(task, "is due!")

    # try to schedule next check at 0 second of next minute
    delay = 60 - now.second
    root.after(delay*1000, sound_alarm)

...

sound_alarm() # start the checking task
root.mainloop()

检查输入任务的时间是否已过

Checking whether a time for an input task has passed

python

tkinter

python-datetime