聚合多个查找和管道 return 仅最后一个元素
Aggregate with multiple lookup and pipeline return only the last element
我尝试了下面的代码,它正在努力从其他集合中查找值。但为什么它只有 return 最后一个元素。
如果我省略展开函数,它 return 都是模型的结果,但第二次查找不会像第一次查找 return 数组那样工作。
我的 objective 是查找包含 templatefolders
集合中表示的模型 ID 的文件夹。
const result = await this.dashboardModel
.aggregate([{ $match: filter }])
.lookup({
from: 'templatefolders',
as: 'template',
let: { id: '$_id' },
pipeline: [
{
$match: {
$expr: {
$and: [
{
$eq: ['$dashboardId', '$$id'],
},
{
$eq: ['$deletedAt', null],
},
],
},
},
},
{
$project: {
_id: 1,
folderId: 1,
},
},
],
})
.unwind('template')
.lookup({
from: 'folders',
as: 'folder',
let: { folderId: '$template.folderId' },
pipeline: [
{
$match: {
$expr: {
$and: [
{
$eq: ['$_id', '$$folderId'],
},
{
$eq: ['$deletedAt', null],
},
],
},
},
},
{
$project: {
_id: 1,
name: 1,
},
},
],
})
.unwind('folder')
.exec();
return result;
结果
{
"data": [
{
...(parent field)
"template": {
"_id": "60ab22b03b39e40012b7cc4a",
"folderId": "60ab080b3b39e40012b7cc41"
},
"folder": {
"_id": "60ab080b3b39e40012b7cc41",
"name": "Folder 1"
}
}
],
"meta": {},
"success": true,
"message": "Succesfully get list"
}
我是前端出身。我希望我的问题不是一个愚蠢的问题。
谢谢!
编辑:
dashboard: [{
_id: dashboard1
}]
templatefolders: [{
dashboardId: dashboard1,
folderId: folder123
}]
folders: [{
_id: folder123
}]
您可以使用$lookup
加入collections
$lookup
加入两个 collections .Lookup doc
$unwind
解构数组。 Unwind doc
$group
重建我们已经解构的数组 Group doc
这是代码
db.dashboard.aggregate([
{
"$lookup": {
"from": "templatefolders",
"localField": "_id",
"foreignField": "dashboardId",
"as": "joinDashboard"
}
},
{
"$unwind": "$joinDashboard"
},
{
"$lookup": {
"from": "folders",
"localField": "joinDashboard.folderId",
"foreignField": "_id",
"as": "joinDashboard.joinFolder"
}
},
{
"$group": {
"_id": "$_id",
"joinDashboard": {
"$push": "$joinDashboard"
}
}
}
])
我尝试了下面的代码,它正在努力从其他集合中查找值。但为什么它只有 return 最后一个元素。
如果我省略展开函数,它 return 都是模型的结果,但第二次查找不会像第一次查找 return 数组那样工作。
我的 objective 是查找包含 templatefolders
集合中表示的模型 ID 的文件夹。
const result = await this.dashboardModel
.aggregate([{ $match: filter }])
.lookup({
from: 'templatefolders',
as: 'template',
let: { id: '$_id' },
pipeline: [
{
$match: {
$expr: {
$and: [
{
$eq: ['$dashboardId', '$$id'],
},
{
$eq: ['$deletedAt', null],
},
],
},
},
},
{
$project: {
_id: 1,
folderId: 1,
},
},
],
})
.unwind('template')
.lookup({
from: 'folders',
as: 'folder',
let: { folderId: '$template.folderId' },
pipeline: [
{
$match: {
$expr: {
$and: [
{
$eq: ['$_id', '$$folderId'],
},
{
$eq: ['$deletedAt', null],
},
],
},
},
},
{
$project: {
_id: 1,
name: 1,
},
},
],
})
.unwind('folder')
.exec();
return result;
结果
{
"data": [
{
...(parent field)
"template": {
"_id": "60ab22b03b39e40012b7cc4a",
"folderId": "60ab080b3b39e40012b7cc41"
},
"folder": {
"_id": "60ab080b3b39e40012b7cc41",
"name": "Folder 1"
}
}
],
"meta": {},
"success": true,
"message": "Succesfully get list"
}
我是前端出身。我希望我的问题不是一个愚蠢的问题。
谢谢!
编辑:
dashboard: [{
_id: dashboard1
}]
templatefolders: [{
dashboardId: dashboard1,
folderId: folder123
}]
folders: [{
_id: folder123
}]
您可以使用$lookup
加入collections
$lookup
加入两个 collections .Lookup doc$unwind
解构数组。 Unwind doc$group
重建我们已经解构的数组 Group doc
这是代码
db.dashboard.aggregate([
{
"$lookup": {
"from": "templatefolders",
"localField": "_id",
"foreignField": "dashboardId",
"as": "joinDashboard"
}
},
{
"$unwind": "$joinDashboard"
},
{
"$lookup": {
"from": "folders",
"localField": "joinDashboard.folderId",
"foreignField": "_id",
"as": "joinDashboard.joinFolder"
}
},
{
"$group": {
"_id": "$_id",
"joinDashboard": {
"$push": "$joinDashboard"
}
}
}
])