如何将 python `dict` 转换为 `sqlalchemy.engine.row`

Question

我知道我们可以通过 row_dict = dict(row) 将 sqlalchemy.engine.row 转换为 dict。是否有可能做相反的事情，即像 row = Row(row_dict) 这样的事情？我试过了，但没有用，错误为 *** TypeError: BaseRow expected 5 arguments, got 1

Answer 1

至少你可以做到

import sqlalchemy as sa

engine = sa.create_engine("sqlite:///:memory:")

# test data
data = {"col1": "foo", "col2": "bar"}

sql = "SELECT " + ", ".join([f":{k} as {k}" for k in data])
print(sql)  # SELECT :col1 as col1, :col2 as col2

with engine.begin() as conn:
    row = conn.execute(sa.text(sql), data).fetchone()

print(type(row))  # <class 'sqlalchemy.engine.row.LegacyRow'>
print(row)  # ('foo', 'bar')
print(row.col1)  # foo

如何将 python `dict` 转换为 `sqlalchemy.engine.row`

How to convert a python `dict` to a `sqlalchemy.engine.row`

python

sqlalchemy