SELECT 的情况 - 未返回预期结果
Case with SELECT - not returning expected results
如果 SC 中的 ContractID 出现在 AT_TMP_ 中,我尝试 return“Y”,如果没有出现,则尝试“N”。
这是我当前的代码 - 目前,“Y”是 returned 无论如何。
注意:T-SQL我很好,PL/SQL& Oracle 对我来说还是比较新
WITH AT_TMP_ AS (
SELECT CONTRACT_ID FROM SC_SERVICE_CONTRACT_CFV WHERE
EXISTS(
SELECT 1
FROM SC_SRV_CONTRACT_INVPLN_cfv cs
WHERE SC_SERVICE_CONTRACT_cfv.CONTRACT_ID = cs.contract_id
AND cs.cf$_invoice_date is null
AND CS.CF$_INV_NOT_REQ_DB = 'FALSE'
))
SELECT SC.CONTRACT_ID, CASE
WHEN
SC.CONTRACT_ID IS NOT NULL THEN 'Y'
ELSE 'N'
END AS YES_NO
FROM SC_SERVICE_CONTRACT_cfv SC
LEFT OUTER JOIN
AT_TMP_
ON AT_TMP_.Contract_ID = SC.Contract_ID;
您需要在AT_TMP_中完成案例。 SC 永远不会为空,因为它位于左联接的左侧。 AT_TMP 可以为空,因为它位于左联接的右侧。
WITH AT_TMP_ AS (
SELECT CONTRACT_ID FROM SC_SERVICE_CONTRACT_CFV WHERE
EXISTS(
SELECT 1
FROM SC_SRV_CONTRACT_INVPLN_cfv cs
WHERE SC_SERVICE_CONTRACT_cfv.CONTRACT_ID = cs.contract_id
AND cs.cf$_invoice_date is null
AND CS.CF$_INV_NOT_REQ_DB = 'FALSE'
))
SELECT SC.CONTRACT_ID, CASE
WHEN
AT_TMP_.CONTRACT_ID IS NOT NULL THEN 'Y'
ELSE 'N'
END AS YES_NO
FROM SC_SERVICE_CONTRACT_cfv SC
LEFT OUTER JOIN
AT_TMP_
ON AT_TMP_.Contract_ID = SC.Contract_ID;
您的 case 表达式目前没有引用 at_tmp_
;您进行了外部联接,但随后对该联接的结果不执行任何操作。您可以更改 case 表达式以检查 CTE 中的值,如 @banana_99 所示。
但您并不真的需要 CTE。可以直接使用exists
检查:
SELECT SC.CONTRACT_ID,
CASE
WHEN EXISTS (
SELECT null
FROM SC_SRV_CONTRACT_INVPLN_cfv SCI
WHERE SCI.CONTRACT_ID = SC.contract_id
AND SCI.cf$_invoice_date is null
AND SCI.CF$_INV_NOT_REQ_DB = 'FALSE'
)
THEN 'Y' ELSE 'N' END AS YES_NO
FROM SC_SERVICE_CONTRACT_cfv SC;
我认为你需要 EXISTS 而不是 LEFT JOIN -
WITH AT_TMP_ AS ( SELECT CONTRACT_ID
FROM SC_SERVICE_CONTRACT_CFV
WHERE EXISTS(SELECT 1
FROM SC_SRV_CONTRACT_INVPLN_cfv cs
WHERE cs.CONTRACT_ID = cs.contract_id
AND cs.cf$_invoice_date is null
AND CS.CF$_INV_NOT_REQ_DB = 'FALSE')
)
SELECT SC.CONTRACT_ID,
CASE WHEN EXISTS (SELECT 1 FROM AT_TMP_
WHERE AT_TMP_.Contract_ID = SC.Contract_ID) THEN 'Y'
ELSE 'N' END AS YES_NO
FROM SC_SERVICE_CONTRACT_cfv SC;
如果 SC 中的 ContractID 出现在 AT_TMP_ 中,我尝试 return“Y”,如果没有出现,则尝试“N”。
这是我当前的代码 - 目前,“Y”是 returned 无论如何。
注意:T-SQL我很好,PL/SQL& Oracle 对我来说还是比较新
WITH AT_TMP_ AS (
SELECT CONTRACT_ID FROM SC_SERVICE_CONTRACT_CFV WHERE
EXISTS(
SELECT 1
FROM SC_SRV_CONTRACT_INVPLN_cfv cs
WHERE SC_SERVICE_CONTRACT_cfv.CONTRACT_ID = cs.contract_id
AND cs.cf$_invoice_date is null
AND CS.CF$_INV_NOT_REQ_DB = 'FALSE'
))
SELECT SC.CONTRACT_ID, CASE
WHEN
SC.CONTRACT_ID IS NOT NULL THEN 'Y'
ELSE 'N'
END AS YES_NO
FROM SC_SERVICE_CONTRACT_cfv SC
LEFT OUTER JOIN
AT_TMP_
ON AT_TMP_.Contract_ID = SC.Contract_ID;
您需要在AT_TMP_中完成案例。 SC 永远不会为空,因为它位于左联接的左侧。 AT_TMP 可以为空,因为它位于左联接的右侧。
WITH AT_TMP_ AS (
SELECT CONTRACT_ID FROM SC_SERVICE_CONTRACT_CFV WHERE
EXISTS(
SELECT 1
FROM SC_SRV_CONTRACT_INVPLN_cfv cs
WHERE SC_SERVICE_CONTRACT_cfv.CONTRACT_ID = cs.contract_id
AND cs.cf$_invoice_date is null
AND CS.CF$_INV_NOT_REQ_DB = 'FALSE'
))
SELECT SC.CONTRACT_ID, CASE
WHEN
AT_TMP_.CONTRACT_ID IS NOT NULL THEN 'Y'
ELSE 'N'
END AS YES_NO
FROM SC_SERVICE_CONTRACT_cfv SC
LEFT OUTER JOIN
AT_TMP_
ON AT_TMP_.Contract_ID = SC.Contract_ID;
您的 case 表达式目前没有引用 at_tmp_
;您进行了外部联接,但随后对该联接的结果不执行任何操作。您可以更改 case 表达式以检查 CTE 中的值,如 @banana_99 所示。
但您并不真的需要 CTE。可以直接使用exists
检查:
SELECT SC.CONTRACT_ID,
CASE
WHEN EXISTS (
SELECT null
FROM SC_SRV_CONTRACT_INVPLN_cfv SCI
WHERE SCI.CONTRACT_ID = SC.contract_id
AND SCI.cf$_invoice_date is null
AND SCI.CF$_INV_NOT_REQ_DB = 'FALSE'
)
THEN 'Y' ELSE 'N' END AS YES_NO
FROM SC_SERVICE_CONTRACT_cfv SC;
我认为你需要 EXISTS 而不是 LEFT JOIN -
WITH AT_TMP_ AS ( SELECT CONTRACT_ID
FROM SC_SERVICE_CONTRACT_CFV
WHERE EXISTS(SELECT 1
FROM SC_SRV_CONTRACT_INVPLN_cfv cs
WHERE cs.CONTRACT_ID = cs.contract_id
AND cs.cf$_invoice_date is null
AND CS.CF$_INV_NOT_REQ_DB = 'FALSE')
)
SELECT SC.CONTRACT_ID,
CASE WHEN EXISTS (SELECT 1 FROM AT_TMP_
WHERE AT_TMP_.Contract_ID = SC.Contract_ID) THEN 'Y'
ELSE 'N' END AS YES_NO
FROM SC_SERVICE_CONTRACT_cfv SC;