SQL 服务器中的 Case 表达式中的 WHEN ELSE

Question

我正在我的 SQL 服务器中编写 case 表达式，我想在 else 块中添加硬编码值。

我想检查 case 表达式，如果下面的 DHB 输出是 2.1 和 ABC001 那么它应该显示 ABC Hospital.

的硬编码值

SELECT DISTINCT
    userid, 
    CASE 
       WHEN CHARINDEX('-', e.name) > 0 
          THEN Ltrim(Rtrim(substring(e.name,0, charIndex('-', e.name)))) 
       ELSE e.name 
    END as DHB      
FROM
    [Table1].[dbo].Event ae
JOIN
    [Portal].[dbo].cUser cu ON cu.name = ae.userID
JOIN
    [Portal].[dbo].UAttribute ua ON ua.cUser = cu.uniqueId
JOIN
    [Portal].[dbo].[EIdentifier] ei ON ei.cUser = cu.uniqueId
JOIN
    [Portal].[dbo].[EIdentifierType] e ON e.uniqueId = ei.externalIdentifierType
WHERE
    (e.name LIKE '%ABC001%' OR e.name LIKE '2.1')
    AND userId = 'Al5'

当前输出

          userid    DHB
           Al5     2.1
           Al5      ABC001
           Bl5     3.1
           Bl5      CDE001

预期输出

          userid    DHB
           Al5     ABC Hospital
           Bl5      EFG Hospital

我在下面尝试过类似的方法

CASE WHEN Ltrim(Rtrim(substring(e.name,0, charIndex('-', e.name)))) = 'ABC001' THEN 'ABC Hospital'
      WHEN e.name = '2.1' THEN 'ABC Hospital'
      ELSE e.name 'ABC Hospital'
  END as DHB

但它不允许我输入 ELSE e.name 'ABC Hospital'。

非常感谢任何帮助！！

Answer 1

我能够解决您的问题并更新查询以满足您的需要。

SELECT DISTINCT userid,
CASE WHEN DHB in ('2.1','ABC001') THEN 'ABC Hospital'
ELSE DHB END 
FROM 
(
SELECT 
    userid, 
    CASE 
       WHEN CHARINDEX('-', e.name) > 0 
          THEN Ltrim(Rtrim(substring(e.name,0, charIndex('-', e.name)))) 
       ELSE e.name 
    END as DHB      
FROM
    [Table1].[dbo].Event ae
JOIN
    [Portal].[dbo].cUser cu ON cu.name = ae.userID
JOIN
    [Portal].[dbo].UAttribute ua ON ua.cUser = cu.uniqueId
JOIN
    [Portal].[dbo].[EIdentifier] ei ON ei.cUser = cu.uniqueId
JOIN
    [Portal].[dbo].[EIdentifierType] e ON e.uniqueId = ei.externalIdentifierType
WHERE
    (e.name LIKE '%ABC001%' OR e.name LIKE '2.1')
    AND userId = 'Al5'
) as aa

SQL 服务器中的 Case 表达式中的 WHEN ELSE

WHEN ELSE in Case expression in SQL Server

sql

tsql

sql-server

case